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pshichka [43]
3 years ago
8

If, after fetching a value from memory, we discover that the system has returned only half of the bits that we expected; it is l

ikely that we have a problem with:______-
a. the I/O bus
b. the system bus
c. byte alignment
d. the control unit
Computers and Technology
1 answer:
Ratling [72]3 years ago
4 0

Answer:

Option c (byte alignment) is the appropriate alternative.

Explanation:

  • This same alignment problem emerges if another architecture does seem to be an application-specific byte, however, the design phrase set education seems to be greater within one byte. In these kinds of case scenarios, because when recovering a significance from people's memories the structure can come back less than half including its bits.
  • If memory access isn't synchronized, it seems to have been unevenly spaced. Recognize that even by interpretation, byte storage access has always been connected.

Some other choices aren't connected to the type of situation in question. So the above is the right option.

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Write, compile, and execute a C program that calculates and returns the fourth root of the number 81.0, which is 3. (hint: The f
alex41 [277]

Answer:

   result=pow(value,0.25);

   printf("The 4th root is:%2.f",result);

Explanation:

In order to accomplish the task we need a library called math.h.

//4 root code

#include <stdio.h>

#include <math.h> //adding the library math.h

int main()

{  

   double value=81.0,root=0.25,result; //declaring the variables

   result=pow(value,root); //The function Pow will return the power raised to the base number

   printf("The 4th root is:%2.f",result); //print the result

   return 0;

}

3 0
3 years ago
What is output?
Misha Larkins [42]

Answer:

The output of code will be 10

Explanation:

We need to find output of following code:

C = 1

Sum = 0

while (c less than 10):

C = c + 3

sum = sum + c

print (sum)

Solution:

We will check the condition of while loop, if the condition is true, then the statements inside the loop will be executed. Since brackets are not available so, only one statement is linked with while loop.

First while loop will be executed c < 10 (1<10) the condition becomes true, and statement c=c+3 will be executed ( 4=1+3) and then loop condition will be checked (4<10) the condition becomes true, and statement c=c+3 will be executed ( 7=4+3) and then loop condition will be checked (7<10) the condition becomes true and statement c=c+3 will be executed ( 10=7+3) and then loop condition will be checked (10<10) the condition becomes false, so we will come outside loop body and execute: sum=sum+c (10=0+10) and print sum i. e 10

So, The output of code will be 10

6 0
3 years ago
Robert’s computer is not working properly. It has become too slow to respond to programs. What can he do to maintain his compute
ozzi

Answer: Utility Software

Explanation:

Utility software is software designed to help to analyze, configure, optimize or maintain a computer. It is used to support the computer infrastructure - in contrast to application software, which is aimed at directly performing tasks that benefit ordinary users.

3 0
3 years ago
ANSWER QUICKLIY
lidiya [134]

Answer:

Explanation:

Allow you to view the document in different ways. Sorry if I am wrong. I am dumb

God bless, stay safe, and good luck! :)

4 0
3 years ago
Read 2 more answers
The questions are in the pictures, i basically have to create a web page, drop the html code and files below thank you.
matrenka [14]

This contains pretty much what you need:


<!DOCTYPE html>



<html>


<head>


   <meta charset="utf-8" />


   <title>The Page Title</title>


</head>


<body>



   <h1>First paragraph</h1>


   <p>This is a paragraph of text.</p>


   <h2>Second level paragraph</h2>


   <p>


       Here is an unordered list of options:


       <ul>


           <li>First</li>


           <li>Second</li>


           <li>Third</li>


       </ul>


       Here is another unordered list of options:


       <ul>


           <li>First</li>


           <li>Second</li>


           <li>Third</li>


       </ul>


       Here is an ordered list of options:


       <ol>


           <li>First</li>


           <li>Second</li>


           <li>Third</li>


       </ol>


   </p>


   <h4>Third level</h4>



</body>


</html>

3 0
4 years ago
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