Answer:
13,33 MIN.
Explanation:
1. Time with Older Computer (OC) = 2 time with New Computer (NC)
2. OC+ NC = 10 MIN.
replacing 1. in 2. OC + OC/2 = 10 min.
1.5 OC =10min
OC=6.66 MIN
NC = 3,33 MIN.
If we replace NC with OC , 3,33 min will take 2 times (6,66 min)
Total Time = 6,66 + 6,66= 13,33 min
Sequence. I took the same test like 5 minutes ago and got a perfect score
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Answer:
right clicking on the desktop and clicking "view"
4. Only (ii)
<u>Explanation:</u>
The declaration of the array can be of two types:
1. int a[100];
2. int[] a = new int[100];
The general thing about an array is that whenever we want to undergo traversal in an array, we always have to start from the 0th position as the size of the array may be a whole number (let us say 10). So, to undergo traversal in an array, we start from 0 to n-1 (in this case 9) such that it covers the size of the array.
The size of an array can be finite or infinite. The general rule is it starts from 0 to n-1 where n is the size of the array. In the above example, the range of the index of the array will be 0 through 100 and not 1 through 100.
