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anygoal [31]
2 years ago
12

−10x + 1 + 7x = 37 i need the answers for that

Mathematics
1 answer:
vaieri [72.5K]2 years ago
4 0
-10x+7x=-3x
3x+1=37
(-1) (-1)
3x=36
(Divide by 3 each side)
3x divided by 3= x
36 divided by 3 = 6
Answer: x=6
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Please omg I need help ASAP please! (Giving brainliest)
snow_lady [41]
Gradient =2 because the slope is 2 units. Y-intercept = -2 because it crosses the y-line at -2.
5 0
2 years ago
Find the area of the triangle
elixir [45]

Answer: The area of the triangle is 252 :)

Step-by-step explanation:

M = 6

L = 6

K = 7

6 x 6 = 36 x 7 = 252

The area of the triangle is 252 :)

5 0
2 years ago
The difference between a and b is 10. The number a is 4 more than 3 times the number b. Which of the following pairs of equation
k0ka [10]

Answer:

D. a−b=10 a=3b+4

Step-by-step explanation:

Difference between a and b means to subtract b from a

We have,

a-b=10

a is 4 more than 3 times b

4 more than means to add 4

3 times b means to multiply b by 3

Therefore, a=3 times b + 4

a=3b+4

a - b=10; a=3b+4

4 0
3 years ago
Please help if u see this
jek_recluse [69]
<h3>Answer: Choice D</h3>

(f \circ g)(x) = x+12

Domain = [-3, infinity)

==================================================

Work Shown:

f(x) = x^2 + 9\\\\f(g(x)) = (g(x))^2 + 9\\\\f(g(x)) = (\sqrt{x+3})^2 + 9\\\\f(g(x)) = x+3 + 9\\\\f(g(x)) = x+12\\\\(f \circ g)(x) = x+12\\\\

In step 2, we replaced every x with g(x)

In step 3, we plugged in g(x) = sqrt(x+3)

The domain of g(x) is [-3, infinity), so this is the domain of (f \circ g)(x) as well since the composite function depends entirely on g(x). Put another way: the input of f(x) depends on the output of g(x), so that's why the domains match up.

7 0
2 years ago
What is the solution to the system of equations below?
sattari [20]

Answer:

<h2>x = 9, y = -36 → (9, -36)</h2>

Step-by-step explanation:

y=-3x-9\qquad(1)\\\\y=\dfrac{1}{3}x-39\qquad(2)\\\\\text{Substitute (1) to (2)}\\\\-3x-9=\dfrac{1}{3}x-39\qquad\text{multiply both sides by 3}\\\\-9x-27=x-117\qquad\text{add 27 to both sides}\\\\-9x=x-90\qquad\text{subtract}\ x\ \text{from both sides}\\\\-10x=-90\qquad\text{divide both sides by (-10)}\\\\x=9

\text{Put the value of x to (1):}\\\\y=-3(9)-9\\\\y=-27-9\\\\y=-36

7 0
3 years ago
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