Question

Solve this please !!!!

Answer 1

$16,000 was invested in the account earning 6% interest and

$10,500 was invested in the account earning 5% interest.

Given that, Ngoc invests a total of $26,500 in two accounts. The first account earned an annual interest rate of 6% and the second account earned an annual interest of 5%. At the end of one year, the total amount of money gained was $1485.

We need to find how much was invested into each account.

What are systems of equations?

A system of equations is a collection of two or more equations with the same set of unknowns. In solving a system of equations, we try to find values for each of the unknowns that will satisfy every equation in the system.

Now,

Let x be the amount of money invested at 6% interest.

Let y be the amount of money invested at 5% interest.

Thus, x +y = 26,500-----(1) and 0.06X + 0.05Y = 1485-----(2)

Multiply 0.06 to the equation x +y = 26,500, so we get 0.06x+0.06y=1,590-----(3)

By subtracting equation (2) from (3), we get

0.01y=105

⇒y=10,500

Substituting y=$10500 in equation (1), we get x=$16,000

Therefore, $16,000 was invested in the account earning 6% interest and

$10,500 was invested in the account earning 5% interest.

To learn more about the system of equations visit:

brainly.com/question/21620502.

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