$16,000 was invested in the account earning 6% interest and
$10,500 was invested in the account earning 5% interest.
Given that, Ngoc invests a total of $26,500 in two accounts. The first account earned an annual interest rate of 6% and the second account earned an annual interest of 5%. At the end of one year, the total amount of money gained was $1485.
We need to find how much was invested into each account.
<h3>What are systems of equations?</h3>
A system of equations is a collection of two or more equations with the same set of unknowns. In solving a system of equations, we try to find values for each of the unknowns that will satisfy every equation in the system.
Now,
Let x be the amount of money invested at 6% interest.
Let y be the amount of money invested at 5% interest.
Thus, x +y = 26,500-----(1) and 0.06X + 0.05Y = 1485-----(2)
Multiply 0.06 to the equation x +y = 26,500, so we get 0.06x+0.06y=1,590-----(3)
By subtracting equation (2) from (3), we get
0.01y=105
⇒y=10,500
Substituting y=$10500 in equation (1), we get x=$16,000
Therefore, $16,000 was invested in the account earning 6% interest and
$10,500 was invested in the account earning 5% interest.
To learn more about the system of equations visit:
brainly.com/question/21620502.
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