Answer:
He owned Cat for 5 years.
Step-by-step explanation:
Given: Owned dog for 9 years.
Dog owned year is one year less than twice as long as he owned a cat.
Lets assume the years that cat has been owned be "x".
Now, finding the number years that Cat hes been owned.
As given, Dog owned year is one year less than twice as long as he owned a cat.
∴ using equation to find the Cat´s owned years.
⇒
adding 1 on both side.
⇒
dividing both side by 2
⇒
∴x=
Hence, Cat has been owned for 5 years.
Combinations = n! / (n - r)! r!
In this case:
n = 4
r = 3
Combinations = 4! /(4-3)! 3! = 24/(1)(6) = 24/6 = 4
Answer:
4 arrangements
Answer:
Adult tickets sold = 225
Student Tickets sold = 375
Step-by-step explanation:
Let:
Adult tickets sold = x
Student Tickets sold = y
Total tickets sold = 600
So, we can write: x+y = 600
Total money collected = 3037.50
Cost of 1 Adult ticket = $6.00
Cost of one Student ticket = $4.50
So, we can write: 6x+4.5y=3037.50
Now, we get a system of equations, that if solved we can find values of x and y
Let:
We can solve using substitution method.
Finding value of x from eq(1) and putting it in eq(2)
Put in eq(2)
So, we get value of y = 375
Now put value of y in eq(1) to find value of x
So, we get value of x = 225
The Tickets sold will be:
Adult tickets sold = x = 225
Student Tickets sold = y = 375