Can someone please help me !!!

Describe how the graph of the function is related to the graph of f(x) = x^2

astraxan [27]

Answer:

a

Step-by-step explanation:

graph show it If you put a number in for x then you can see the different

4 0

3 years ago

Read 2 more answers

What are the x and y-intercepts of the line described by the equation?

tatuchka [14]

Answer: x=4.41 y= -7.35

Step-by-step explanation:

Pretty basic just graph them using Desmos...

Showing your work you would need to get x on one side then y on the other.

Because 3y is positive I personally like to use that one first. The inverse operation of 3y is divide so you divide 3y by 3 and the 3s cancel out. Divide -22.05 by 3 and you get -7.35. Which is your y value.

Finding X is a bit more difficult, you need to divide by -5 which is the obvious inverse operation. So, -22.05/-5 and you get 4.41. Which is your X value.

Any further questions feel free to contact me.

-Vy

5 0

3 years ago

Do the equations x + y = -2 and 3x + 3y = −6 define the same line? Explain.

tino4ka555 [31]

Answer:

Yes, they do.

Step-by-step explanation:

They both pass through the same points of -2 on the x and y axis.

6 0

3 years ago

. Approximate each of the following logarithms to four decimal places. Use the LOG key on your calculator rather than logarithm

Free_Kalibri [48]

Answer:

$log_2(6)=2.584$

Step-by-step explanation:

Here the logarithm has base 2

$log_2(3^2)=log_2(6)$

Let

$log_2(6)=x$

$log_ya=x\\\Rightarrow y^x=a$

$\\\Rightarrow 2^x=6$

Now, take logarithm to the base 10

$log 2^x=log6\\\Rightarrow xlog2=log6\\\Rightarrow x=\frac{log6}{log2}\\\Rightarrow x=2.584$

So, $log_2(6)=2.584$

5 0

3 years ago

How do you check is the equation is a extraneous solution pr not?

vampirchik [111]

We can check the equation is an extraneous solution or not by finding the solution and plugging it in the equation, to verify it.

<h3>What is the extraneous solution?</h3>

In mathematics, an extraneous solution is a solution that comes from the process of solving the problem but is not a genuine solution to the problem, such as the answer to an equation.

As we know from the definition the extraneous solution is a solution that comes from the process of solving the problem but is not a genuine solution to the problem.

Let's suppose the equation is:

$\rm \sqrt{x+4} = x -2$

Squaring both the sides:

x + 4 = (x - 2)²

x + 4 = x² - 4x + 4

x² -5x = 0

x = 0 or x = 5

Checking for the solution by plugging in the equation;

$\rm \sqrt{5+4} = 5 -2$

3 = 3

$\rm \sqrt{0+4} = 0 -2$

2 ≠ -2

The solution x = 0 shows extraneous solution.

Thus, we can check the equation is an extraneous solution or not by finding the solution and plugging it in the equation, to verify it.

Learn more about the extraneous solution here:

brainly.com/question/14054707

#SPJ1

6 0

2 years ago