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solniwko [45]
3 years ago
8

PLS PLS PLS HELP ME! I WILL GIVE BRAINILIEST!

Mathematics
1 answer:
mihalych1998 [28]3 years ago
6 0

Answer:

I'm going to answer in the comments so no one steals this answer

Step-by-step explanation:

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The value of the 8th term is 78.
trapecia [35]

Answer:

108

Step-by-step explanation:

4 0
3 years ago
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
3 years ago
I need to know what’s the the length
Monica [59]

Answer:

b=4

Step-by-step explanation:

P.T.c^2=a^2 +b^2

5^2=3^2 +b^2

25=9+b^2

b^2 =25-9

b^2 =16

b=sqrt(16)

b=4

8 0
4 years ago
Anyone have any idea? i dont have any idea
ladessa [460]

Answer:

\tt f(x)=2x^2+20x-10

let y=f(x)

\tt y=2x^2+20x-10

\tt 2x^2+10x=y+10

\tt x^2+10x=\frac{1}{2} y+5

\tt x^2+10x+25=\frac{1}{2} y+30

\tt (x+5)^2=\frac{1}{2} (y+60)

\tt 2(x+5)^2=f(x)+60

\boxed{\tt f(x)=2(x+5)^2-60}

Hope it helps! :)

8 0
2 years ago
A take-and-bake pizza chain has several
tankabanditka [31]
Answer: 35% off coupon

Explanation:
17.90-5= 12.90

x/17.90=35/100
Cross multiply: 17.90(35)=100x
Simplify: 626.50=100x
Divide by 100: 6.265
Round: 6.27
Subtract: 17.90-6.27=11.63
8 0
4 years ago
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