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suter [353]
4 years ago
8

If z is a positive integer, does 4 + 3(2z-5) represent a number that is greater than,less than ,or equal to 2(3z-4)? Please show

me how you got the answer.
Mathematics
2 answers:
EastWind [94]4 years ago
5 0

Answer:

The number will be greater than 2(3z-4)

Step-by-step explanation:

Thinking process:

Let the expressions be:

4 + 3(2z-5)            ...1

and

2(3z-4)                 ...2

Now, let z be a positive number, say 2

Substituting gives:

4 + 3(2*2-5) = 7     ...1

and

2(3*2-4)        = 4     ...2

As it can be seen from the solutions, the expression 4 + 3(2z-5)  will be greater than  2(3z-4) for any value of z.

That is,  4 + 3(2z-5) > 2(3z-4) for any real value of z.

DochEvi [55]4 years ago
4 0
4 + 3( 2(4) - 5)
= 4 + 24-5
= 28-5
= 23

2(3(4) -4)
= 2(12) -4
= 24 -4 = 20



4+3(2z-5) > 2(3z-4)
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Find the measure of an angle who's measure is 20 less than the measure of its supplement.
Dvinal [7]

supplementary angles add up to 180°.


x = measure of such angle


x + 20 = measure of her sibling.


since "x" has 20 less than her sibling, then clearly her sibling has to have 20 more than "x".


\bf (x)+\stackrel{sibling}{(x+20)}=180\implies 2x+20=180\implies 2x=160 \\\\\\ x=\cfrac{160}{2}\implies x=80

7 0
3 years ago
Jamal earns $40 washing 5 windows. At this rate, how many windows did Jamal wash to earn $80?​
Alja [10]
10 windows : divide 40/5=8
Then divide 80/8 =10
3 0
3 years ago
Read 2 more answers
Rafeeq bought a field in the form of a quadrilateral (ABCD)whose sides taken in order are respectively equal to 192m, 576m,228m,
Valentin [98]

Answer:

a. 85974 m²

b. 17,194,800 AED

c. 18,450 AED

Step-by-step explanation:

The sides of the quadrilateral are given as follows;

AB = 192 m

BC = 576 m

CD = 228 m

DA = 480 m

Length of a diagonal AC = 672 m

a. We note that the area of the quadrilateral consists of the area of the two triangles (ΔABC and ΔACD) formed on opposite sides of the diagonal

The semi-perimeter, s₁,  of ΔABC is found as follows;

s₁ = (AB + BC + AC)/2 = (192 + 576 + 672)/2 = 1440/2 = 720

The area, A₁, of ΔABC is given as follows;

Area\, of \, \Delta ABC = \sqrt{s_1\cdot (s_1 - AB)\cdot (s_1-BC)\cdot (s_1 - AC)}

Area\, of \, \Delta ABC = \sqrt{720 \times (720 - 192)\times  (720-576)\times  (720 - 672)}

Area\, of \, \Delta ABC = \sqrt{720 \times 528 \times  144 \times  48} = 6912·√(55) m²

Similarly, area, A₂, of ΔACD is given as follows;

Area\, of \, \Delta ACD= \sqrt{s_2\cdot (s_2 - AC)\cdot (s_2-CD)\cdot (s_2 - DA)}

The semi-perimeter, s₂,  of ΔABC is found as follows;

s₂ = (AC + CD + D)/2 = (672 + 228 + 480)/2 = 690 m

We therefore have;

Area\, of \, \Delta ACD = \sqrt{690 \times (690 - 672)\times  (690 -228)\times  (690 - 480)}

Area\, of \, \Delta ACD = \sqrt{690 \times 18\times  462\times  210} = \sqrt{1204988400} = 1260\cdot \sqrt{759} \ m^2

Therefore, the area of the quadrilateral ABCD = A₁ + A₂ = 6912×√(55) + 1260·√(759) = 85973.71 m² ≈ 85974 m² to the nearest meter square

b. Whereby the cost of 1 meter square land = 200 AED, we have;

Total cost of the land = 200 × 85974 = 17,194,800 AED

c. Whereby the cost of fencing 1 m = 12.50 AED, we have;

Total perimeter of the land = 576 + 192 + 480 + 228 = 1,476 m

The total cost of the fencing the land = 12.5 × 1476 = 18,450 AED

4 0
3 years ago
A round swimming pool (a cylinder) has a diameter of 16 feet and a height of 4 feet. How many gallos of water can the pool hold
Marina CMI [18]
If my calculations aren't off, it is approximately 80.43. 
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3 years ago
The perimeter of a square is 40cm.then area of a square is
quester [9]

Answer:

100

Step-by-step explanation:

40/4 =10 which are the side and 10*10 =100 which is the area

7 0
3 years ago
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