First you must know that is i∧2= -1
x∧3-4x∧2+4x-16 = x∧2 (x-4) + 4 (x-4) = (x-4) (x∧2+4) = (x-4) (x∧2-(-4)) =
= (x-4) (x∧2-(-1) *4) = (x-4) (x∧2- i∧2*2∧2) = (x-4) (x∧2-(2i)∧2) = (x-4) (x-2i) (x+2i)
Good luck!!!
Answer:
5
Step-by-step explanation:
4.5*10^-8/ 9*10^-9
1) Reduce the fraction, express 9 as a product of multiplying 4.5*2
4.5*10^-8/4.5*2*10^-9
2) Then notice the common factor of numerator and denominator( 4.5) , get rid of it in both numerator and dnominator
3) 10^-8/ 2*10^-9= 1/2*(10^-8/10^-9)= 0.5* (10^-8/10^-9)
10^-8/10^-9= 10^(-8-(-9))= 10^1=10.
so 0.5*10=5 (it is the answer written in scientific form)
Answer:
I believe it does
Step-by-step explanation:
32000 times .05
Step-by-step explanation:
ur gonna go 6 to the left and 5 up
