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VashaNatasha [74]
3 years ago
11

Suppose the x-intercept of f(x) is (p,0) and the x-intercept of g(x) is (q,0). What is the value of p+q?

Mathematics
1 answer:
Mice21 [21]3 years ago
3 0

Answer:

The answer is C

Step-by-step explanation

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Write the equation of the line with the given slope and y- intercept. 1.Slope is -2 and a y-intercept of 5.
Monica [59]

Since the slope is -2, then m=-2. Since the y-intercept is 5, b=5. Then, we can create the equation: y=-2x+5


Since the slope is \frac{3}{4}, then m=\frac{3}{4}. Since the y-intercept is -3, b=-3.

Then, we can create the equation: y=\frac{3}{4}x-3



5 0
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Nate bought two large pizzas and one small pizza and paid $36 if the difference in costs between the large and small pizza is $5
goldenfox [79]

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Step-by-step explanation:

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4 0
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In order to solve for the variable in the equation 1-(x+2)+ 2X= 5(2x-5)- Mikel first applies the distributive property.
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6 0
3 years ago
Which characteristics will prove that ΔDEF is an acute, isosceles triangle?
ololo11 [35]

Answer:

  a.  segment DE and segment EF are congruent to each other but not to segment DF, and their slopes are not related.

Step-by-step explanation:

In order for a triangle to be isosceles, two of the line segments must be congruent. (eliminates choices C and D)

If the slopes of the congruent segments are negative reciprocals of each other, the triangle is a right triangle, not an acute triangle. (eliminates choice B)

With choices B, C, D eliminated, we are left with choice A.

__

However, <em>that necessary description is not sufficient</em> to constrain the triangle to be an acute triangle. In order for the triangle to be acute, the third side must be less than √2 times the length of either of the congruent sides.

The correct answer is "none of the above."

3 0
3 years ago
Find the value of x.<br> 8<br> 5<br> X + 20<br><br> I need help please
Deffense [45]

Answer:

x=-\frac{68}{9}

Step-by-step explanation:

\frac{9}{14}=\frac{8}{x+20}\\

9(x+20)=8*14\\9x+180=112\\9x=-68\\x=-\frac{68}{9}\\

5 0
3 years ago
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