We don't know the amount they get but the equation would be Claire 5 + a
Answer:

Step-by-step explanation:
The cotangent of theta is:

For pi/2 < theta< pi
This means that the angle is in the second quadrant. In the second quadrant, the cosine is negative and the sine is positive. This means that the cotangent will be negative.
Secant:

In this question

So

Using cross multiplication



Now we apply the following trigonometric identity:






Since the angle is in the second quadrant, the sine is positive.

Finally, the cotangent:



Answer:
f(x) = x^3 - x^2 -2x
Step-by-step explanation:
If x = a is a zero of a polynomial, then x-a is a factor of the polynomial. Given the factors of a polynomial, the polynomial can be obtained by multiplying the factors.
The factors of the given polynomial are;
x - 2
x + 1
x
Multiplying the first two factors;
(x-2)(x+1) = x^2 + x -2x -2
= x^2 -x -2
We finally multiply this result by x to obtain our polynomial;
f(x) = x ( x^2 -x -2)
= x^3 - x^2 -2x
which is a cubic polynomial since it has 3 roots.
( - 10, - 22 )
using the midpoint formula,
let the other endpoint have coordinates (x, y) then
(2 + x ) = - 4 ( multiply through by 2 )
2 + x = - 8 ( subtract 2 from both sides ) then
x = -8 - 2 = - 10 ← value of x-coordinate
Similarly for y-coordinate
(8 + y ) = - 7 ( multiply through by 2 )
8 + y = - 14 ( subtract 8 from both sides )
y = - 14 - 8 = - 22 ← y -coordinate
the other endpoint is ( - 10, - 22 )
Answer:
8m(m+1) /3
Step-by-step explanation:
2m/3 (m+4) +2m (m/3-2)
=2m²/3 + 8m/3 + 2m²
=2m²/3 + 8m/3 + 6m²
=8m²/3 + 8m/3
=8m(m+1)/3