Answer:
yes
Step-by-step explanation:
Answer:
0.6848
Step-by-step explanation:
Mean of \hat{p} = 0.453
Answer = 0.453
Standard deviation of \hat{p} :
= \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} = \sqrt{\frac{0.453(1-0.453)}{100}} = 0.0498
Answer = 0.0498
P(0.0453 - 0.05 < p < 0.0453 + 0.05)
On standardising,
= P(\frac{0.0453-0.05-0.0453}{0.0498} <Z<\frac{0.0453+0.05-0.0453}{0.0498})
= P(-1.0044 < Z < 1.0044) = 0.6848
Answer = 0.6848
Answer:
179200000000
Step-by-step explanation:
Answer:
I say its number 2
Step-by-step explanation:
