Answer:
<em>Dividend</em>
Step-by-step explanation:
Dividend is a number that is to be divides by other.
So 100 is a dividend.
25:
A divisor.
A divisor is a number to be divided by.
4:
Result of the division
Answer:
Rate = 6.56%
Step-by-step explanation:
Principal (P) = $5000
Interest (I) = $6312
Time (T) = 4 years
Rate (r) = ?
This question is involves simple interest and with the formula, we can easily plug in the values to find the rate.
S.I = P(1 + rt)
S.I = simple interest
P = principal
R = Rate
T = Time
6312 = 5000(1 + r*4)
6312 = 5000 + 5000*4r
6312 - 5000 = 20000r
1312 = 20000r
r = 1312 / 20000
r = 0.0656
Rate are calculated in percentage hence we'll multiply it by 100
R = 6.56%
m = -1
Step-by-step explanation:
-16m = 7 + 9
-16m = 16
m = 16 ÷ -16
m = -1
The solutions to the given equation containing absolute value term |3x-7| - 7 = x are 0 and 7.
<h3>What are the solutions to the given equation?</h3>
Given the equation in question;
|3x-7| - 7 = x
First, add 7 to both sides.
|3x-7| - 7 + 7 = x + 7
|3x-7| = x + 7
Next, remove the absolute value term, this creates a ± on the right side of the question.
|3x-7| = x + 7
3x-7 = ±( x + 7 )
The complete solution is the result of both the negative and positive portions of the solution.
For the first solution, use the positive of ±.
3x-7 = ( x + 7 )
3x - 7 = x + 7
3x - x = 7 + 7
2x = 14
x - 14/2
x = 7
For the second solution, use the negative of ±.
3x-7 = -( x + 7 )
3x-7 = -x - 7
3x + x = -7 + 7
4x = 0
x = 0/4
x = 0
Therefore, the solutions to the given equation containing absolute value term |3x-7| - 7 = x are 0 and 7.
Learn to solve more equation involving absolute value term here: brainly.com/question/28635030
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Answer:
log₂(3) = 1.585 ≠ 1.5
Her thinking is not valid because the technique of average is valid only if the graph of the function is a straight line, but the graph of the log function is not a straight line.
Therefore the values cannot be taken by average
Step-by-step explanation:
Given:
log₂(2) = 1
log₂(4) = 2
To evaluate : log₂(3)
Now,
we know that
logₓ(y) = 
(Here the log has same base in the numerator and the denominator i.e 10)
therefore,
log₂(3) = 
also,
log(2) = 0.3010
log(3) = 0.4771
thus,
log₂(3) = 
or
log₂(3) = 1.585 ≠ 1.5
Her thinking is not valid because the technique of average is valid only if the graph of the function is a straight line, but the graph of the log function is not a straight line.
Therefore the values cannot be taken by average
