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3 years ago

(4/5)-2 solution simplify the equation

Mathematics

2 answers:

pickupchik [31]3 years ago

6 0

Answer:

Solution is $\frac{-6}{5}$

Step-by-step explanation:

$\frac{4}{5} - 2$

Set common denominators

$\frac{4}{5} - \frac{10}{5}$

Subtract

$\frac{4}{5} - \frac{10}{5} = \frac{-6}{5}$

Andre45 [30]3 years ago

3 0

Step-by-step explanation:

first we will take comman then

$\frac{4}{5} - \frac{2 \times 5}{5}$

then 4 - 10

it will be

$\frac{6}{5}$

$1 \frac{1}{5}$

i hope it will help

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Traders joes sold 7981 bags of tortilla chips recently. If 1178 of these bags were fat free find the percent that were fat free.

lawyer [7]

Answer:

14.76% of tortilla chips bag were fat free.

Step-by-step explanation:

We are given the following in he question:

Number of bags of tortilla chips sold = 7981

Number of bags hat were fat free = 1178

We have to find the percentage of bags that were fat free.

Percentage:

$\dfrac{\text{Number of fat free bags}}{\text{Total number of bags}}\times 100\%\\\\=\dfrac{1178}{7981}\times 100\%\\\\=14.76\%$

Thus, 14.76% of tortilla chips bag were fat free.

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3 years ago

How to graph transformations of quadratic functions

miskamm [114]

Answer:

Shift "h" units to the right, "k" units up, and reflect over the x or y axis when needed.

Step-by-step explanation:

1) I want to talk about reflections first.

Reflections across the x-axis --> $y = ax^2$ , a is the coefficient. if a is negative, then the equation should be reflected across the x-axis. This is known as a vertical reflection.
Reflections across the y-axis --> $y=a(bx)^2$ , b is the coefficient. If b is negative, then reflect the equation over the y-axis. There are cases where the reflection across the y-axis does not change anything. But, let's say its $y=(x-3)^2$ ... the reflection across the y-axis is different (that equation is: $y=(-x-3)^2$ )

2) Rigid transformations

Horizontal transformations (to the left or right): $y=a(bx-h)^2$ , factor out b from "bx-h" and whatever h equals is the units to the right. If h is a negative number, then you move to the left.
Vertical transformations (up and down): $y = a(bx-h)^2+k$ ... k is just the units up... if k is negative then we move it down.

Example (check image for visual)

We transform $y = x^2$ to $y = -(-x-3)^2+3$ , you move right 3, then reflect across the x-axis, then reflect across y-axis, then move 3 up.

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Note: In the image, the red line is the original function, the blue one is the transformed function. See if you can follow along with the verbal instructions I gave above.