What grade is that is that 4th or 5th grade
Answer:
67.5feet
Step-by-step explanation:
Given parameters:
Model distance between building and gymnasium = 22.5 inches
Scale of model : 1 inch = 3 feet
Unknown:
Actual ground distance = ?
To solve this problem, we first must understand the concept of scale. A scale is a relationship that represents a dimension on a map/model compared to the true ground expression. In order to visualize or represent some real life objects on paper or in a computer, we use models. These models are an abstraction of the real world based on scales. There are different ways of representing a scale.
In this problem;
the scale is given as;
1 inch on model represents 3 feet on ground
Now, to find 22.5 inches, simply cross multiply and solve;
If 1 inch on model represents 3 feet on ground
22.5 inches on a model will be = 
= 67.5feet
Therefore, the actual distance is 67.5feet
Answer:
784m^2
Step-by-step explanation:
is a rectangle with sides of 40m and 20m, in the upper right corner a right triangle has been removed with the legs of: 40 - 32 = 8m and 20 - 16 = 4m, we find the area of the rectangle (b * h).
40 * 20 = 800m ^ 2, then we find the area of the right triangle
1/2 b * h: 1/2 8 * 4 = 16 m ^ 2.
we remove the area of the triangle from the rectangle and we have the area of the figure: 800 - 16 = 784m^2
The expression representing the distance is
0
13y-2b=15y
2b=2y
2b=2y
2b=2y