Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Answer:
IT SHOULD BE 240
Step-by-step explanation:
1) Multiply 20 by 10 for 200
2) Lenght=20 so half is 10
3) multiply 10 by 4 and divide by 2 which gives 20
4) Multiply 20 by 2 because there are 2 rectangles which gives us 40
5) Add 200 and 40 which gives answer of 240
So check the picture below
recall your SOH CAH TOA
which identity uses only
angle
opposite
adjacent?
well, is Ms Tangent.. thus
solve for "x", make sure your calculator is in Degree mode, since the angle is in degrees
Answer:
Step-by-step explanation:
When a transversal crosses parallel lines, the interior same-side angles are supplementary. That means ...
a° and 36° are supplementary, so
a = 180 - 36 = 144
and
b° and 113° are supplementary, so
b = 180 -113 = 67
_____
The bases of this trapezoid are parallel, as indicated by the right-pointing arrow on each one. The left- and right-ends of the trapezoid are lines between the parallel bases that meet the requirement for the marked angles next to each one to be supplementary.
Answer:
d.4
Step-by-step explanation:
28−(5)(4)−4
=28−20−4
=8−4
=4
