No, they are not like terms because they cannot be added together. 5x^2 is squared, whereas 2x is not. Though they both have x variables attached to them, they are not like terms because one is squared and the other is not. Examples of like terms include 5 and 8, 4y and 7y, 8z^2 and 10z^2.
Hope this helps!! :)
Step-by-step explanation:
option B is correct as,
10 + x = -18
→ x = -18 -10
→ x = -28
<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps </u></em><em><u>you </u></em><em><u>dear.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care</u></em><em><u>!</u></em>
Answer:
126
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
The equation of a circle is
(x-h)^2 + (y-k)^2 = r^2
h= 9, k = -7
r = 2, so r^2 = 4.
We now know that the equation must equal 4, so we can rule out answers A and C.
Plug in the values for h and k to get
(x-9)^2 + (y+7)^2 = 4
Choice B is correct!
Well, I'm not completely sure, because I don't know the formal definition
of "corner" in this work. It may not be how I picture a 'corner'.
Here's what I can tell you about the choices:
A). (0, 8)
This is definitely a corner of the feasible region.
It's the point where the first and third constraints cross.
So it's not the answer.
B). (3.5, 0)
This is ON the boundary line between the feasible and non-feasible
regions. But it's not a point where two of the constraints cross, so
to me, it's not what I would call a 'corner'.
C). (8, 0)
Definitely not a corner, no matter how you define a 'corner'.
This point is deep inside the non-feasible zone, and it doesn't
touch any point in the feasible zone.
So tome, this looks like probably the best answer.
D). (5, 3)
This is definitely a corner. It's the point of intersection (the solution)
of the two equations that are the first two constraints.
The feasible region is a triangle.
The three vertices of the triangle are (0,8) (choice-A),
(0,-7) (not a choice), and (5,3) (choice-D) .
region is a triangle
