Hello I think the answer would be three.
Answer:
Let p represent the # of pages in the book. Then, Nora has already read 0.30p pages and has 0.70p pages left to read.
If she reads 25% pages/night, that means reading 0.25(0.70)p pages per night, or 17.5 pages/night. If 28% p/n, that means 0.28(0.70)p pages/night, or 19.6p pages/night.
How many nights will it take Nora to finish the book if she reads 25% of 7/10 of the book per night? Without any calculations, we can answer this by "4 nights, since she reads 1/4 of the unread portion of the book per night."
If she reads 28% of 7/10 of the book per night, that will require fewer nights:
First night: 28%
Second night: 28%
Third night: 28%
Total: 3(28%) = 84%
This leaves 16% to read on the final night.
This is one interpretation of what I think is a poorly worded question.
The author of this question might have meant reading 25% of the remaining unread pages per night, which leads to a different answer.
According to the Central Limit Theorem, the distribution of the sample means is approximately normal, with the mean equal to the population mean (1.4 flaws per square yard) and standard deviation given by:

The z-score for 1.5 flaws per square yard is:

The cumulative probability for a z-score of 1.11 is 0.8665. Therefore the probability that the mean number of flaws exceeds 1.5 per square yard is
1 - 0.8665 = 0.1335.
Answer:
Step-by-step explanation:
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