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AnnyKZ [126]
3 years ago
12

Please help. Use PEMDAS

Mathematics
2 answers:
german3 years ago
4 0
This order,

P: Parentheses

E: Exponents

M: Multiplication

D: Division

A: Addition

S: Subtraction
Masja [62]3 years ago
3 0
Answer is 5. Add 6 and 4. Subtract 6 from 8. Multiply both answers by 2. Divide 20 by 4
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4/5 dived by 3/4<br><br> Please help
Leto [7]

Answer:

1 1\15

Step-by-step explanation:

5 0
3 years ago
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Write the equation in slope-intercept form through the point (-4, -7) and is perpendicular to the line y = -(7/4)x + 4 and graph
Scilla [17]

You have to write the equation for a line that crosses the point (-4, -7) and is perpendicular to the line

y=-\frac{7}{4}x+4

When you have to determine a line that is perpendicular to a known line, you have to keep in mind that the slope of the perpendicular line will be the negative inverse of the first one.

If for exampla you have two lines, the first one being:

y_1=mx+b

And the second one, that is perpedicular to the one above:

y_2=nx+c

The slope of the second one is the negative inverse of the first one:

n=-\frac{1}{m}

The slope of the given line y=-7/4+4 is m=-7/4

So the slope of the perpendicular line has to ve the inverse negative of -7/4

\begin{gathered} n=-(-\frac{4}{7}) \\ n=\frac{4}{7} \end{gathered}

Considering it has to pass through the point (-4,-7) and that we already determined its slope, you can unse the point slope formula to determine the equation of the perpendicular line:

y-y_1=m(x-x_1)

replace with the coordinates of the point and the slope and calculate:

\begin{gathered} y-(-7)=\frac{4}{7}(x-(-4)) \\ y+7=\frac{4}{7}(x+4) \\ y+7=\frac{4}{7}x+\frac{16}{7} \end{gathered}

Subtract 7 to both sides of the equation to write it in slope-intercept form:

\begin{gathered} y+7-7=\frac{4}{7}x+\frac{16}{7}-7 \\ y=\frac{4}{7}x-\frac{33}{7} \end{gathered}

Now you can graph both lines

8 0
1 year ago
Consider triangle ABC. The legs have a length of 5 units each. What is the length of the hypotenuse of the triangle?
Korvikt [17]

Answer:

5\sqrt{2} units.

Step-by-step explanation:

We have been given that two legs of triangle ABC measures 5 units each. We are asked to find the length of the hypotenuse.

We will use Pythagoras theorem to solve for the hypotenuse of triangle ABC.

\text{Hypotenuse}^2=\text{Leg}^2+\text{Leg}^2

Substituting our given values in above equation we will get,

\text{Hypotenuse}^2=5^2+5^2

\text{Hypotenuse}^2=25+25

\text{Hypotenuse}^2=50

Upon taking square root of both sides of our equation we will get,

\text{Hypotenuse}=\sqrt{50}

\text{Hypotenuse}=\sqrt{25*2}

\text{Hypotenuse}=5\sqrt{2}

Therefore, the length of hypotenuse of triangle ABC is 5\sqrt{2} units.

6 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST
Kaylis [27]

Answer:

7x+80

Step-by-step explanation:

7 times everything in the () and get

56+7x+24

combine like terms

7x+80

3 0
3 years ago
Read 2 more answers
Can anyone help me with 5 and 7 ​
Alexxx [7]

Answer:

4) add 5x and 9x

 answer:   14x - 30

7) subtract 28 from 15

answer: x - 13

Step-by-step explanation:  sorry if it is wrong I try my best

5 0
3 years ago
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