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2 years ago

HELP WITH MATH IF YOU DON'T KNOW THE ANSWER THEN GET OUT OF THE QUESTION

Mathematics

1 answer:

34kurt2 years ago

4 0

Answer:

1.79 or 43/24

Step-by-step explanation:

179 pregunta 43/24

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Need answer ASAP please

bulgar [2K]

Answer:

0.44444444444, round it to the tenth or hundredth or wherever it tells you to round the answers to.

5 0

3 years ago

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Use the equation below to find a, if b = 5 and c = 12<br><br> a = 27 - b - c

vovikov84 [41]

Answer: 10

a=27-5-12=10

5 0

3 years ago

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I need help or the answer

loris [4]

Answer:

5x+4y = 52

Step-by-step explanation:

We can first write the equation in point slope form

y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point

y - 8 = -5/4 ( x-4)

Multiply each side by 4 to get rid of the fraction

4(y - 8) = 4*(-5/4) ( x-4)

4(y - 8) = -5 ( x-4)

Distribute

4y - 32 = -5x+20

We want the equation in the form

Ax + By = C

Add 5x to each side

5x+4y -32 = -5x+5x+20

Add 32 to each side

5x+4y -32+32 =32+20

5x+4y = 52

4 0

3 years ago

Bob has a recipe for salad dressing. The recipe says to mix 14 c lemon juice, 18 c mustard, and 14 c vinegar. How much lemon jui

Alex73 [517]

Answer:

He needs 56c of lemon juice to make 4 salad dressings.

Step-by-step explanation:

We only need to look at how much lemon juice to make one salad dressing which would be 14c so we have to make 4 so we would do 14x4 to get how much lemon juice you need to make 4 dressings so you would need 56c of lemon juice to make 4 dressings

7 0

3 years ago

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A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte

ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, $q_1 = Q- r \times Q$

$q_1 = Q(1-r)\cdots(i)$

The value of quantity after 2 months, $q_2 = q_1- r \times q_1$

$q_2 = q_1(1-r)$

From equation (i)

$q_2=Q(1-r)(1-r) \\\\q_2=Q(1-r)^2\cdots(ii)$

The value of quantity after 3 months, $q_3 = q_2- r \times q_2$

$q_3 = q_2(1-r)$

From equation (ii)

$q_3=Q(1-r)^2(1-r)$

$q_3=Q(1-r)^3$

Similarly, the value of quantity after n months,

$q_n= Q(1- r)^n$

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

$q_{48}=Q(1-r)^{48}$

Putting Q=6200 and r=5.5%=0.055, we have

$q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32$

Hence, the value of quantity after 4 years is 410.32.

4 0

3 years ago

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