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2 years ago

HELP WITH MATH IF YOU DON'T KNOW THE ANSWER THEN GET OUT OF THE QUESTION

Mathematics

1 answer:

34kurt2 years ago

4 0

Answer:

1.79 or 43/24

Step-by-step explanation:

179 pregunta 43/24

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The dollar value v (t) of a certain car model that is t years old is given by the following exponential function.

galina1969 [7]

Answer:

$ 3820

Step-by-step explanation:

When the car is new, it is 0 year old. It means, t = 0

Initial value = 26,000 (0.84)^0 = 26,000(1)

Initial value = $ 26000

Similarly, when car is 11 year old, t = 11

=> 26000(0.84)¹¹ = 26000(0.14691)

≈ $ 3819.842

≈ $ 3820 (round to near ten)

6 0

2 years ago

Helpppp plzzzzzzzzzzzzzzz

marin [14]

Answer:

y= 0.2(0.05)^x

5 0

2 years ago

Yearly tuition, housing, and fees for a local college are $10,500, $1300, and $2170 respectively. You have saved $3100 and have

Natalija [7]

Answer:

4,370

Step-by-step explanation:

add 10,500, 1,300, and 2,170

then add 3,100 and 6,500

subtract both sums

got it

4 0

3 years ago

The cafeteria has 6 round tables and 23 rectangular chairs tables. If each round table has 7 chairs ,and each rectangular table

shtirl [24]

Answer:

456

Step-by-step explanation:

Number of chairs around the round tables = 6×7=42

Number of chairs around the rectangular tables =23×18=414

The total number of chairs in the cafeteria = 6×7+23×18=456

4 0

3 years ago

Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun

WITCHER [35]

Answer:

Required solution (a) $f(x,y,z)=xyz+3z^2+C$ (b) 40.

Step-by-step explanation:

Given,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k$

(a) Let,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}$

Then,

$f_x=yz,f_y=xz,f_z=xy+6z$

Integrating $f_x$ we get,

$f(x,y,z)=xyz+g(y,z)$

Differentiate this with respect to y we get,

$f_y=xz+g'(y,z)$

compairinfg with $f_y=xz$ of the given function we get,

$g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)$

Then,

$f(x,y,z)=xyz+h(z)$

Again differentiate with respect to z we get,

$f_z=xy+h'(z)=xy+6z$

on compairing we get,

$h'(z)=6z\implies h(z)=3z^2+C$ (By integrating h'(z)) where C is integration constant. Hence,

$f(x,y,z)=xyz+3z^2+C$

(b) Next, to find the itegration,

$\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40$

3 0

3 years ago