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2 years ago

Wallace bought 4 gallons of milk last week because his family drinks a lot of milk. If

1 answer:

6 0

6 days. There are 4 quarts in 1 gallon so there are 16 quarts in all. Since they drinks 3 quarts everyday, we divide 16 by 3. The answer is 5.3 but I rounded it up because the question asks how many days will it take for the family to finish all the 4 gallons.

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Which ordered pair is a solution to the equation y+1=3(x-4)

Talja [164]

Answer:

(0,-13),(1,-10),(2,-7)

Step-by-step explanation:

Hope this helps! Please mark as brainliest.

Thanks!

7 0

3 years ago

Pls help ! <br> simplify

Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

Sqaure roots can be rewritten as fractions.

The numerator will be rewritten as 6^(1/4)

The denominator will he written as 6^(1/5)

Now u can subtract the power, but u have to find a common denominator so it is now (5/20)-(4/20)

The denominator stays the same so you are left with 1/20 which is still the power over 6

6^1/20

4 0

3 years ago

Read 2 more answers

3 gallons coverted to cups

Oksana_A [137]

3 gallons converted to cups is 48 cups

6 0

3 years ago

The graph represents data from an experiment.

Nina [5.8K]

Answer:

skewed left i believe please mark brainlist if this was correct if not let me know and i can review it!

have a great day, you deserve to treat yourself !!

Step-by-step explanation:

5 0

2 years ago

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0

2 years ago