I’ll do an example problem, and I challenge you to do this on your own!
4x+6y=23
7y-8x=5
Solving for y in 4x+6y=23, we can separate the y by subtracting both sides by 4x (addition property of equality), resulting in 6y=23-4x. To make the y separate from everything else, we divide by 6, resulting in (23-4x)/6=y. To solve for x, we can do something similar - subtract 6y from both sides to get 23-6y=4x. Next, divide both sides by 4 to get (23-6y)/4=x.
Since we know that (23-4x)/6=y, we can plug that into 7y-8x=5, resulting in
7*(23-4x)/6-8x=5
= (161-28x)/6-8x
Multiplying both sides by 6, we get 161-28x-48x=30
= 161-76x
Subtracting 161 from both sides, we get -131=-76x. Next, we can divide both sides by -76 to separate the x and get x=131/76. Plugging that into 4x+6y=23, we get 4(131/76)+6y=23. Subtracting 4(131/76) from both sides, we get
6y=23-524/76. Lastly, we can divide both sides by 6 to get y=(23-524/76)/6
Good luck, and feel free to ask any questions!
Answer:
Option B. 5 hours
Step-by-step explanation:
The tennis club charges monthly fees = $50.00
and per hour charges of court time = $10.00
Lets assume you play number of hours in a month = x hr
So, per hour charges would be = $10x
Total payment = monthly charges + charges of played hours
$100.00 = $50.00 + 10x
10x = 100 - 50
10x = 50
x = 5
Option B. You used 5 hours court time.
Hope this helps ! Answer =1/2f19 and picture
If you have three quarters and each is a value of 25¢ you add and get 75¢ and you add the $4 which gives you $4.75
If she lost 1/3 of her bows and still had 42, that means she had 63 bows before school because 1/3 of 63 is 21 and 63-21=42. If she got 7 for her birthday then 63-7=56. She had 56 bows before her birthday
