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N76 [4]
3 years ago
5

13. (a) A man bought two books for Rs 1040. He sold one at a loss of 15% and other at a profit of 36%

Mathematics
1 answer:
gavmur [86]3 years ago
8 0

Answer:

Let the price of one book be Rs. x

price of next book is = 1040 - X

C.P of 1st book is Rs. x

Loss = 15%

S.P of 1st book = 85x / 100

C.P of 2nd book = 1040 - X

Profit = 36%

S.P of 2nd book = (1040 - x × 136)/100

(85x)/ 100 - (1040 - x × 136) / 100

85 x= 1040 x 136 - 136 x

85 x + 136 x= 1040 × 136

221 x = 1040 x 136

X = (1040 x 136) / 221

X = 640

So, Cost price for 1st book is 640 Rs. and 2nd book is 1040 - 640 = 400 Rs.

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You can again ignore the parenthesis because you are not distributing anything. 
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Answer: Store D: 36 pack for $8.00

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<h3>STEP - BY - STEP EXPLANATION</h3>

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You have to divide the amount of money by the pack number. So A would be 0.25 cents per soda. B would be 0.25 cents per soda. C would be 0.26 cents per soda. And finally, D would be 0.22 cents per soda. Therefore Store D would be the best buy.

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The equation of the graph y= x^{3}-2x^{2} +3x-4 has no symmetry

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