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Irina18 [472]
3 years ago
5

How much of the total population of the earth does 16 people make up?

Mathematics
2 answers:
Nataliya [291]3 years ago
7 0

Answer:

Australia/New Zealand (56%), Northern Africa and Western Asia (46%), Australia/New Zealand (28%), Central and Southern Asia (25%), Latin America and the Caribbean (18%), Eastern and Southeastern Asia (3%), and Europe and Northern America (2%).

Step-by-step explanation:

eduard3 years ago
5 0

Answer:

16 people ÷ total population × 100%

16÷7900000000×100%

(16/7900000000×100)% of people.

calculate and find the answer, hope the explanation helped

BY GERALD GREAT

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Lilit [14]

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3 years ago
Hi please help with this question ???):
maw [93]
The answer to your question is -19
7 0
3 years ago
Read 2 more answers
Jed Sites
g100num [7]

Answer:

Option B: 3x + 3y - 3

Step-by-step explanation:

In an isosceles triangle, the two congruent sides are equal.

We are told the base is; x - y - 2 units

Now let each of the congruent sides be represented as A.

Thus the perimeter equation will be;

P = 2A + x - y - 2

Now, we are told that the perimeter is; 7x + 5y - 8 units

Thus;

7x + 5y - 8 = 2A + x - y - 2

Rearranging gives;

7x - x + 5y + y - 8 + 2 = 2A

2A = 6x + 6y - 6

Divide through by 2 to give;

A = 3x + 3y - 3 units

6 0
3 years ago
Item 32 On three 150-point geography tests, you earned grades of 88%, 94%, and 90%. The final test is worth 250 points. What per
stira [4]
97.2% on the final.
Find the total amount of points needed to get a 93%. 150+150+150+250 = 700 total points. 700*.93 = 651 total points needed to get 93%. find the points received from the other quizzes and subtract the sum from 651 to find how many points need to be scored on the final.
150*.88=132 (test 1)
150*.94=141 (test 2)
150*.90=135 (test 3)
132+141+135= 408

651-408 = 243 points to score on the final exam.
243/250 =.972 or 97.2%
3 0
3 years ago
Given that f(x) = x + 3<br> a) Find f(2)
Nataly_w [17]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

In the above question, it is given that :

\qquad \sf  \boxed{ \sf f(x) =  \frac{x + 3}{2} }

A.) Find f(2) :

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{2 + 3}{2}

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{5}{2}

or

\qquad \sf  \dashrightarrow \: f(2) = 0.5

B.) Find { \sf {f}^{-1}(x) } :

\qquad \sf  \dashrightarrow \: let \: y = f (x)

so, we can write it as :

\qquad \sf  \dashrightarrow \: y =  \dfrac{x + 3}{2}

\qquad \sf  \dashrightarrow \: 2y = x + 3

\qquad \sf  \dashrightarrow \: x = 2y - 3

Now, put x = { \sf {f}^{-1}(x) }, and y = x and we will get our required inverse function ~

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3

C.) Find { \sf {f}^{-1}(12) } :

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33

7 0
1 year ago
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