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algol13
3 years ago
7

Geometry class there are 15 boys and 10 girls. The students are presenting projects to the class. If Mrs. Brown selects students

at random for presentations, what is the probability that the first 2 students chosen are girls?
Mathematics
2 answers:
yaroslaw [1]3 years ago
8 0
2/25 chance that this could happen
Luda [366]3 years ago
8 0
The probability is 2/25
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You put $800 in a savings account. The account earns 4% simple interest per year.
nalin [4]

Answer:

A. 160

B. 960

Step-by-step explanation:

The interest earned after 5 years is the balance - the initial balance: 160

The balance is 800 * (1 + .04*5): 960

4 0
3 years ago
Write 321.35 in scientific form.​
konstantin123 [22]

Answer:

3.2135 x 10^2 if you're looking for scientific notation

Step-by-step explanation:

8 0
3 years ago
Best Buy is having a sale on computers. Katherine picks out a computer that was originally $1099.99
borishaifa [10]

Answer:

$901.9918

Step-by-step explanation:

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7 0
3 years ago
I need the volume for 9,11,and 13
mihalych1998 [28]

Hey there!

<h3>Question 1</h3>

Let's use 3.14 for pi during this. It'll make it a lot easier.

The volume for a cone is \pi r^{2} \frac{h}{3}.

The diameter of this cone is 17.6 inches. Since the radius is half the diameter, we can find the radius by dividing this amount by 2.

17.6 ÷ 2 = 8.8

The height of this cone is 23.4 inches.

Plug the values into the equation.

\pi 8.8^{2} \frac{23.4}{3}

Next, square 6.8 and divide 23.4 by 3. Also, replace the pi symbol with 3.14.

3.14 * 77.44 * 7.8

Multiply the numbers together.

<u>The volume of this cone is approximately 1896.66 cubic inches.</u>

<h3>Question 2</h3>

Finding the volume of a trapezoidal prism can be done by finding the are of the trapezoidal face and multiplying it by the depth.

Formula for finding the area of a trapezoid is a = \frac{1}{2} h(b_{1} +b_{2} )

The two bases are 10 and 34, and the height is 24.7 feet. Put these values into the equation.

a = \frac{1}{2} 24.7(10 +34 )

Add 10 and 34, then multiply it by 24.7 and 1/2.

a = 543.4

Multiply that value by 19, which is the depth of the figure.

<u>The volume of the prism is 10324.6 cubic feet.</u>

<h3>Question 3</h3>

The formula for volume of a triangular pyramid is v = 1/3ah, with a the area of the base and h the height.

The formula for the area of an equilateral triangle, which is the base, is a = \frac{\sqrt{3} }{4} s^{2}

The length of the side is 12, so we can square that to get 144.

Now multiply that by \frac{\sqrt{3} }{4} to get the area of the base.

The area of the base is about 62.35 square meters.

The height of the pyramid is 20 meters. Plug that and the area of the base into the equation.

v = 1/3 x 62.35 x 20

Multiply the numbers together to get the volume.

<u>The volume of the pyramid is approximately 415.67 cubic meters.</u>

Hope this helps!

3 0
3 years ago
Experian would like to test the hypothesis that the average credit score for an adult in Virginia is different from the average
aliya0001 [1]

Answer:

a. We fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

b. The 95% confidence interval for the true difference of means is -2.2468 and 36.2468. There is a probability of 95% that the true difference of means \mu_{1}-\mu_{2} is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

Step-by-step explanation:

Let \mu_{1}-\mu_{2} be the true difference between the average credit score for an adult in Virginia and the average credit score for an adult in North Carolina. We have the large sample sizes n_{1} = 40 and n_{2} = 35, the unbiased point estimate for \mu_{1}-\mu_{2} is \bar{x}_{1} - \bar{x}_{2}, i.e., 699-682 = 17.

The standard error is given by \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}, i.e.,

\sqrt{\frac{(44)^{2}}{40}+\frac{(41)^{2}}{35}} = 9.8198.

a. We want to test H_{0}: \mu_{1}-\mu_{2} = 0 vs H_{1}: \mu_{1}-\mu_{2} \neq 0 (two-tailed alternative). The rejection region is given by RR = {z | z < -1.96 or z > 1.96} where -1.96 and 1.96 are the 2.5th and 97.5th quantiles of the standard normal distribution respectively. The test statistic is Z = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}} and the observed value is z_{0} = \frac{17}{9.8198} = 1.7312. Because 1.7312 does not fall inside RR, we fail to reject the null hypothesis.

b. The endpoints for a 95% confidence interval for \mu_{1}-\mu_{2} is given by 17\pm (z_{0.05/2})9.8198, i.e., 17\pm (z_{0.025})9.8198 where z_{0.025} is the 2.5th quantile of the standard normal distribution, i.e., -1.96, so, we have 17-(1.96)(9.8198) and 17+(1.96)(9.8198), i.e., -2.2468 and 36.2468. There is a probability of 95% that the true difference of means \mu_{1}-\mu_{2} is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

3 0
3 years ago
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