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Alex73 [517]
2 years ago
5

Please help i only have a few minutes left!!

Mathematics
2 answers:
Darina [25.2K]2 years ago
6 0

Answer:

VI

Step-by-step explanation:

The letter "A" is a vowel and a capital letter, so this should be categorized in group VI, where the vowel circle and the capital letter circle overlap.

telo118 [61]2 years ago
3 0

Answer:

F

Step-by-step explanation:

It is a capital letter and a vowel

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66.64 rounded to the nearest cent
Zolol [24]
It would just be 66.6
4 0
3 years ago
The combined math and verbal scores for students taking a national standardized examination for college admission, is normally d
kipiarov [429]

Answer:

The minimum score that such a student can obtain and still qualify for admission at the college = 660.1

Step-by-step explanation:

This is a normal distribution problem, for the combined math and verbal scores for students taking a national standardized examination for college admission, the

Mean = μ = 560

Standard deviation = σ = 260

A college requires a student to be in the top 35 % of students taking this test, what is the minimum score that such a student can obtain and still qualify for admission at the college?

Let the minimum score that such a student can obtain and still qualify for admission at the college be x' and its z-score be z'.

P(x > x') = P(z > z') = 35% = 0.35

P(z > z') = 1 - P(z ≤ z') = 0.35

P(z ≤ z') = 1 - 0.35 = 0.65

Using the normal distribution table,

z' = 0.385

we then convert this z-score back to a combined math and verbal scores.

The z-score for any value is the value minus the mean then divided by the standard deviation.

z' = (x' - μ)/σ

0.385 = (x' - 560)/260

x' = (0.385×260) + 560 = 660.1

Hope this Helps!!!

8 0
3 years ago
What is the GCF of 4and 2
Hoochie [10]

Answer:

2

Step-by-step explanation:

GCF stands for the "greatest common factor." Therefore because 2 can go into both 2 and 4 evenly, it is the GCF.

3 0
3 years ago
I can’t find the area
evablogger [386]
Divide it into chunks of area you can find. One way to divide it is
.. a rectangle 2 mi x 5 mi at upper left.
.. a rectangle 8 mi x 6 mi down the middle
.. a rectangle 3 mi x 4 mi at lower right
.. a triangle 5 mi x 6 mi at lower left

Then the sum of areas is
.. (2 mi)*(5 mi) +(8 mi)*(6 mi) +(3 mi)*(4 mi) + (1/2)*(5 mi)*(6 mi)
.. = 10 mi^2 +48 mi^2 +12 mi^2 +15 mi^2
.. = 85 mi^2
4 0
3 years ago
Which ordered pair in the form (a, b) is a solution of this equation?
allochka39001 [22]
3(7)-4(0)=21
3*7=21-0=21
the answer is D
5 0
3 years ago
Read 2 more answers
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