Part 1We are given

. This can be rewritten as

.
Therefore, a=1, b=-18, c=0.
Using the quadratic formula

The values of x are
Part 2Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a
quadratic function. Part 3.The first equation is

.
The second equation is

.
We have

Factoring, we have

Equating both factors to zero.

When the value of x is 6, the value of y is

When the value of x is -3, the value of y is

Therefore, the solutions are (6,38) or (-3,11)
Is there a picture of the shape, and is 4x - 2 AC or AB?
X^2/2 = 7x
x^2 = 14x
x^2 - 14x = 0
A quadratic equation is of the form ax^2 + bx + c
Therefore, in 3x^2 + 5x + 7, c = 7