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alukav5142 [94]
3 years ago
14

A shirt is on sale for $42. If this is (3)/(5) of the original price of the shirt, what was the original price of the shirt?

Mathematics
1 answer:
daser333 [38]3 years ago
8 0
B. 3/5 if 42 would be 25.20$
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PLEASE HELP ME IN FINANCE!!
borishaifa [10]

Answer:

A

Step-by-step explanation:

if we had a economic turn down, basically people would lose money, so that means the consumers, so the producers will have a bunch of left over products because the people can't afford to buy as much, which means the company loses money, which means the employees must be let go of so the business doesn't go out of business

7 0
4 years ago
I need help again.lol
Monica [59]

Answer:

13\ units

Step-by-step explanation:

One is asked to find the distance between two points on a coordinate plane. The easiest way to do so is to use the distance formula, this formula is the following:

D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2

Where ((x_1,y_1)) and ((x_2,y_2)) are the points which one needs to find the distance between. In this case, these points are as follows:

k\ (-3,5)

j\ (-8, -7)

Substitute these points into the formula and solve for the distance between these points,

D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2

D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2

Simplify,

D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2

D=\sqrt{(-3+8)^2+(5+7)^2

D=\sqrt{(5)^2+(12)^2

D=\sqrt{25+144}

D=\sqrt{169}

D=13

8 0
3 years ago
I need help solving this: <img src="https://tex.z-dn.net/?f=x-%20%5Csqrt%7B2x-7%7D%20%3D%205" id="TexFormula1" title="x- \sqrt{2
laila [671]

Hope this helps :).  

6 0
3 years ago
Read 2 more answers
The coefficients in the expression of (x+y)^4 are
DENIUS [597]

Answer:

the coefficients are 1,4,6,4,1.

Step-by-step explanation:

I hope this helps

4 0
3 years ago
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
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