Let's say a = number of ordered soups, b = number of ordered sandwiches.
Then 4.5a + 7.75b = 113.50, and a and b are integers between 0 and 18 inclusive.
How do we tackle this? If all ordered soup, the cost would be $81, so we'll have at least 4 sandwiches. If all ordered sandwich, the cost would be $139.5, so at most 15 sandwiches were ordered. You also know an even number of sandwiches was ordered, to let the price end at 50 cent.
If you brute-force from 4,6,8,10,12 to 14 sandwiches, you find the answer at 10 sandwiches and 8 soups.
10*7.75 + 8*4.50 = 113.50
Step-by-step explanation:
so first convert it into an algebraic equation
4 - ⅛w = 16
⅛w = 16-4
⅛w = 12
w=12÷ 
w=12×8=96
check: 4 - ⅛(96)=4-12=-8
-8<16 (-8 less than 16)
please mark brainliest
Answer:
x=9
Step-by-step explanation:
3x+9=35
3x+9-9=35-9
3x=27
3x/3=27/3
x=9
Answer:
The asnwer i fro 5/2 iss 2.5 and the other question is the answer is 1.3 is we add now is 3.8
Step-by-step explanation:
Answer:
360 mi/h
Step-by-step explanation:
The speed for the outbound trip was ...
speed = distance/time = (715 mi)/(2 1/6 h) = 330 mi/h
The inbound speed was ...
(715 mi)/(1 5/6 h) = 390 mi/h
The airspeed of the plane is the average of these two ground speeds, so is ...
(330 +390)/2 = 360 . . . . mi/h
