To find this, first find the factor or rate of which the numbers are moving. To do so do as follows.
subtract 1 from 3
3-1=2
So each number is having 2 added to it.
Now add two to 7 and the numbers afterwards till you get the 12th term
7+2=9
1+3+5+7+9
9+2=11
1+3+5+7+9+11
11+2=13
1+3+5+7+9+11+13
13+2=15
1+3+5+7+9+11+13+15
15+2=17
1+3+5+7+9+11+13+15+17
17+2=19
1+3+5+7+9+11+13+15+17+19
19+2=21
1+3+5+7+9+11+13+15+17+19+21
21+2=23
1+3+5+7+9+11+13+15+17+19+21+23
So 23 is the 12th term
Answer:
![P(t=14) = 17000 (1-0.1225)^{14}= 2728.404](https://tex.z-dn.net/?f=P%28t%3D14%29%20%3D%2017000%20%281-0.1225%29%5E%7B14%7D%3D%202728.404)
Step-by-step explanation:
for this case we have the following model for the cost of the car:
![P(t) = P_o (1-r)^t](https://tex.z-dn.net/?f=P%28t%29%20%3D%20P_o%20%281-r%29%5Et)
Where
is the initial amount on this case 17000, t the amount of years after the initial year and r the depreciation rate on this case:
![r= \frac{12.25}{100}=0.1225](https://tex.z-dn.net/?f=%20r%3D%20%5Cfrac%7B12.25%7D%7B100%7D%3D0.1225)
And for t =14 we can replace into the equation and we got:
![P(t=14) = 17000 (1-0.1225)^{14}= 2728.404](https://tex.z-dn.net/?f=P%28t%3D14%29%20%3D%2017000%20%281-0.1225%29%5E%7B14%7D%3D%202728.404)
49,400-20,000=29400
29400/24=1225 average miles per month
Answer:
your answer would be A.)12
Step-by-step explanation: You needed to find out what number you can put for it to add up to the number on the bottom line, 17. So you would add (12+5=17) , And you would get the same number as the number on the bottom line.
~hope this explanation has helped~
Answer:
= -716060
Step-by-step explanation: