Answer:
x + 3y = 21
Step-by-step explanation:
![(x_{1},y_{1})=(12,3) \\\\(x_{2},y_{2})=(-3,8)\\\\Slope= \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\= \dfrac{8-3}{-3-12}= \dfrac{5}{-15}\\\\= \dfrac{-1}{3}](https://tex.z-dn.net/?f=%28x_%7B1%7D%2Cy_%7B1%7D%29%3D%2812%2C3%29%20%5C%5C%5C%5C%28x_%7B2%7D%2Cy_%7B2%7D%29%3D%28-3%2C8%29%5C%5C%5C%5CSlope%3D%20%5Cdfrac%7By_%7B2%7D-y_%7B1%7D%7D%7Bx_%7B2%7D-x_%7B1%7D%7D%5C%5C%5C%5C%3D%20%5Cdfrac%7B8-3%7D%7B-3-12%7D%3D%20%5Cdfrac%7B5%7D%7B-15%7D%5C%5C%5C%5C%3D%20%5Cdfrac%7B-1%7D%7B3%7D)
Equation of the line: y =mx+ b
![y = \dfrac{-1}{3}x+b\\\\\\Plugin \ x = 12 \ and \ y=3 \ in \ the \ above \ equation\\\\3= \dfrac{-1}{3}*12+b\\\\3= -4+b\\\\3+4 = b\\\\b = 7\\\\\\\y= \dfrac{-1}{3}x+7\\\\](https://tex.z-dn.net/?f=y%20%3D%20%20%5Cdfrac%7B-1%7D%7B3%7Dx%2Bb%5C%5C%5C%5C%5C%5CPlugin%20%5C%20x%20%3D%2012%20%5C%20and%20%5C%20y%3D3%20%5C%20in%20%5C%20the%20%5C%20above%20%5C%20equation%5C%5C%5C%5C3%3D%20%5Cdfrac%7B-1%7D%7B3%7D%2A12%2Bb%5C%5C%5C%5C3%3D%20-4%2Bb%5C%5C%5C%5C3%2B4%20%3D%20b%5C%5C%5C%5Cb%20%3D%207%5C%5C%5C%5C%5C%5C%5Cy%3D%20%20%5Cdfrac%7B-1%7D%7B3%7Dx%2B7%5C%5C%5C%5C)
Multiply the equation by 3
3y = -x + 21
x + 3y = 21
Answer:
A
Step-by-step explanation:
Only graph A satisfies the domains provided
Answer:
The <em>required probability</em> is
.
Step-by-step explanation:
Let <em>A </em>be the event of rolling the number cube.
Let <em>B</em> be the event of tossing the coin.
Total number of possibilities of rolling the number cube and tossing the coin are <em>12 </em>here.
![\{(1,H),(2,H),(3,H),(4,H),(5,H),(6,H),(1,T),(2,T),(3,T),(4,T),(5,T),(6,T)\}](https://tex.z-dn.net/?f=%5C%7B%281%2CH%29%2C%282%2CH%29%2C%283%2CH%29%2C%284%2CH%29%2C%285%2CH%29%2C%286%2CH%29%2C%281%2CT%29%2C%282%2CT%29%2C%283%2CT%29%2C%284%2CT%29%2C%285%2CT%29%2C%286%2CT%29%5C%7D)
where <em>H</em> means Head on toss of coin and <em>T</em> means Tails on toss of coin.
Formula for probability of an event <em>E</em> is:
![P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}](https://tex.z-dn.net/?f=P%28E%29%20%3D%20%5Cdfrac%7B%5Ctext%7BNumber%20of%20favorable%20cases%7D%7D%7B%5Ctext%20%7BTotal%20number%20of%20cases%7D%7D)
Here, we have to find the probability of event 'E' i.e. getting a 6 on number cube and heads on coin.
Number of favorable cases are <em>1 </em>and total cases are <em>12</em>.
![\Rightarrow P(E) = \dfrac{1}{12}](https://tex.z-dn.net/?f=%5CRightarrow%20P%28E%29%20%3D%20%5Cdfrac%7B1%7D%7B12%7D)
8 x 2 + 6x + 5=0
16 + 6x + 5=0
6x+21=0
6x+21-21=0-21
6x=-21
6x/6=-21/6
x=-7/2
Answer:
-6
Step-by-step explanation:
Please mark as Brainliest! :)