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weqwewe [10]
3 years ago
11

What is the arc length of an arc with radius 14 in and central angle 66^o? Show all calculations that lead to the answer and inc

lude units.
Mathematics
1 answer:
Bas_tet [7]3 years ago
5 0

Answer:

28pi*66/360

Step-by-step explanation

Used the equation Central angle/360*2pi r

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Write 4 3/7 as a decimal.
Citrus2011 [14]
Hi!

There are two ways to do this. 

1. Start with the first part of the decimal, (4.) then divide 3/7 to get the second part. 

3/7 = 0.43

4.43

2. Convert the mixed number 4 3/7 to a fraction. 

4 x 7 = 28
28 + 3 = 31

31/7

Now convert that into a decimal.

31/7 = 4.43

The answer is 4.43

Hope this helps! :)
3 0
3 years ago
Read 2 more answers
there are 3 red marbles,4 blue marbles,2 green marbles, 6 clear marbles in a burlap bag. One marble is randomly pulled from the
creativ13 [48]
2/15 so 13.3% ?

I’m not entirely sure if this is right but I think it’s getting there...
4 0
3 years ago
Use the integer tiles to evaluate the following expressions. 6 + 3 = 6 + (–4) = 6 + (–6) =
babunello [35]

Given:

The expressions are:

6+3

6+(-4)

6+(-6)

To find:

The value of given expression by using integer tiles.

Solution:

We have,

6+3

Here, both number are positive. When we add 6 and 3 positive integer tiles, we get 9 positive integer tiles as shown in the below figure. So,

6+3=9

Similarly,

6+(-4)

Here, 6 is positive and -4 is negative. It means we have 6 positive integer tiles and 4 negative integer tiles.

When we cancel the positive and negative integer tiles, we get 2 positive integer tiles as shown in the below figure. So,

6+(-4)=2

6+(-6)

Here, 6 is positive and -6 is negative. It means we have 6 positive integer tiles and 6 negative integer tiles.

When we cancel the positive and negative integer tiles, we get 0 integer tiles as shown in the below figure. So,

6+(-6)=0

Therefore, 6+3=9, 6+(-4)=2,6+(-6)=0.

8 0
3 years ago
b> Find the equation to the straight lines passing through (1,1) and parallel to the lines represented by x²-5xy+4y²+x+2y-2=0
olasank [31]

please mark brainlist...

4 0
2 years ago
Find the value of the variable such that the value of 5−a is 20 greater than the value of 6a−1
ryzh [129]
<h3>Answer:</h3>

a = -2

<h3>Explanation:</h3>

We want (5-a) to be 20 more than (6a-1). Then we can write ...

... (5-a) = (6a-1) +20

If we add (a-19) to both sides, we get

... -14 = 7a

... -2 = a . . . . . divide by 7

_____

<em>Comment on the graph</em>

In the attached, we use the variable x, because this graphing calculator likes variables named x and y. We graph each expression and find the place where they both have the same value for the same value of x (the point of intersection). The value of the variable x at that point is -2, the solution we seek.

5 0
3 years ago
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