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weqwewe [10]
3 years ago
11

What is the arc length of an arc with radius 14 in and central angle 66^o? Show all calculations that lead to the answer and inc

lude units.
Mathematics
1 answer:
Bas_tet [7]3 years ago
5 0

Answer:

28pi*66/360

Step-by-step explanation

Used the equation Central angle/360*2pi r

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Use the spinner below for each of the following
spayn [35]
The answer is : impossible
3 0
2 years ago
What is the equation of a line that is perpendicular to the line y=3x-6 and passes through the point (15,5)?
Goshia [24]

the fouth option is correct ans....

3 0
3 years ago
8 and 1/4 + 3 and 5/6
k0ka [10]

Answer:

12 1/12

Step-by-step explanation: so, we have to make the bottom number the same as eachother or we will not be able to add effectively. So the first number that both 4 and 6 go into is 12, as you can see if we count by the numbers to get to the answer

4,8,12

6,12

So, now that we have that part figured out we would then have to multiply the top the same amount as we multiplied the bottom. So 1/4x3 and 5/6x2

So we would multiply both the top and the bottom the same amount.

1/4x3=3/12

5/6x2=10/12

So now that we have that figured out everything else is pretty straight forward.

We would add the whole numbers with eachother and the fractions with eachother.

8+3=11

3/12+10/12=13/12


so we can see that it would equal, 11 and 13/12 or 12 and 1/12

8 0
1 year ago
given that the center of a circle is at point (-3,5) and that the radius of the circle is 6 units, write the the equation of the
Anika [276]
The equation of a cricle is 
(x-h)^{2}+(y-k)^{2}=r^{2}
h being the x coordinate of the given point and k being the y coordinate of the given point (r also being the radius). 

Now we have to plug the points into the equation 
(x--3)^{2} +(y-5)^{2} = 6^{2}
now just simplify the the equation
(x+3)^{2} +(y-5)^{2} = 36 
3 0
3 years ago
4x+5y=-13;5x-2y=-8 solve elimination method <br> Step by step
goldfiish [28.3K]
4x + 5y = -13
2(4x + 5y) = 2(-13)
8x + 10y = -26 (equation 1)

5x - 2y = -8
5(5x - 2y) = 5(-8)
25x - 10y = -40 (equation 2)

equation 1 + equation 2,
(8x + 10y) + (25x - 10y) = (-26) + (-40)
8x + 10y + 25x - 10y = -26 + -40
33x = -66
x = -2

substitute x = -2 into equation 1,
8x + 10y = -26
8(-2) + 10y = -26
-16 + 10y = -26
10y = -10
y = -1

The values of x and y are -2 and -1 respectively.
8 0
3 years ago
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