Answer:
-4.99
1.9435
3.25E4
1.56e-9
Step-by-step explanation:
Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
1.
a.11/12=less than one
b. 77/72= greater than one
c.23/60= less than one
d. 31/56= less than one
2. <
Answer:
B. 70%
Step-by-step explanation:
7/10 of the numbers are more than 5
7/10= 70%
