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9966 [12]
2 years ago
5

Which numbers are integers?!?!??

Mathematics
1 answer:
djverab [1.8K]2 years ago
3 0

Answer:

1 and 0

Step-by-step explanation:

i had that

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What is the common difference of 80,60,45,33.75
GenaCL600 [577]

Answer:

The common difference (or common ratio) = 0.75

Step-by-step explanation:

i) let the first term be a_{1} = 80

ii) let the second term be a_{2}  = a_{1} . r = 80 × r = 60      ∴  r = \frac{60}{80} = 0.75

iii) let the third term be     a_{3}  = a_{2} . r = 60 × r = 45      ∴  r = \frac{45}{60} = 0.75

iv) let the fourth term be   a_{4} = a_{3} . r = 45 × r = 33.75   ∴ r = \frac{33.75}{45} = 0.75

Therefore we can see that the series of numbers are part of a geometric progression and the first term is 80 and the common ratio = 0.75.

4 0
3 years ago
A farmer owns a total of 10 acres of land. The land is separated into 4 2/3 equally sized sections. How many acres are in each s
Ostrovityanka [42]

Answer:

I will solve the question and answer

7 0
2 years ago
between 1995 and 2006, the population of samburg, usa(in thousands) can be modeled by f(x) = 0.35x(squared) - 2.1x+15.8 where x=
Juli2301 [7.4K]
\bf f(x)=0.35x^2-2.1x+15.8\qquad 
\begin{cases}
x=\textit{year since 1995}\\
f(x)=\textit{population amount}
\end{cases}

the equation is a quadratic one, and it has a positive coefficient on the leading term, meaning, is opening upwards, so it has a "burrow" for the vertex.

the minimum or lowest point for a quadratic opening upwards is, well, the vertex point :),   the "x" value is the year, the "y" or f(x) value is the population, we're asked for the year, or the x-coordinate of the vertex

well   \bf \begin{array}{llll}
f(x)=&0.35x^2&-2.1x&+15.8\\
&\quad \uparrow &\quad \uparrow&\uparrow \\
&\quad  a&\quad  b &c
\end{array}
\\\\

\\\\
\qquad  \textit{vertex of a parabola}\\ \quad \\
\qquad 

\left(\boxed{-\cfrac{{{ b}}}{2{{ a}}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
5 0
3 years ago
How many times could 6 go into 6
saveliy_v [14]
6 can only go into 6 once
7 0
3 years ago
If fence poists are to be placed in a row 7 feet apart, how many posts are needed for 210 feet of fence?
ollegr [7]

Answer:

31

Step-by-step explanation:

210 ft ÷ 7 ft = 30

There are 30 7-ft lengths of fence.

Think of putting a post at the end of each 7-ft length. That means you need 30 posts. Now you must add 1 post for the beginning.

Answer: 31

8 0
2 years ago
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