I got 480 square feet. I assume that the apartment was a rectangle so the sides were 3in by 5in. Then I converted inches to feet and then found the area again
<span>when p = -24 and q = 4. p/2q= -24/8 = -3 </span>
Answer: The answer is ![\textup{The other root is }\dfrac{8}{3}~\textup{and}q=40.Step-by-step explanation: The given quadratic equation is[tex]3x^2+7x-q=0\\\\\Rightarrow x^2-\dfrac{7}{3}x-\dfrac{q}{3}=0.](https://tex.z-dn.net/?f=%5Ctextup%7BThe%20other%20root%20is%20%7D%5Cdfrac%7B8%7D%7B3%7D~%5Ctextup%7Band%7Dq%3D40.%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%20%20%3C%2Fstrong%3EThe%20given%20quadratic%20equation%20is%3C%2Fp%3E%3Cp%3E%5Btex%5D3x%5E2%2B7x-q%3D0%5C%5C%5C%5C%5CRightarrow%20x%5E2-%5Cdfrac%7B7%7D%7B3%7Dx-%5Cdfrac%7Bq%7D%7B3%7D%3D0.)
Also given that -5 is one of the roots, we are to find the other root and the value of 'q'.
Let the other root of the equation be 'p'. So, we have

and

Thus, the other root is
and the value of 'q' is 40.
Answer:
1.125
Step-by-step explanation:
Answer:
f = 10, g = 4.8 cm
Step-by-step explanation:
Area of ABCE = 60 cm²
Area of ABCD = 48 cm²
So,
Area of ADE = 60-48
=> 12 cm²
Area of ADE = 
<u><em>Where Area = 12 cm², Base = 4 cm</em></u>
12 = 
Height = 12-2
Height = 10 cm
Where Height is AD
So, AD = 10 cm
Also, <u><em>AD is parallel and equal to BC</em></u>
<u><em></em></u>
So,
f = 10 cm
<u><em>Now, Finding g</em></u>
Area of ABCD = 
<u><em>Where Area = 48 cm², Base = 10 cm</em></u>
48 = 10 * Height
Height = 48/10
Height = 4.8 cm
Whereas, Height is g
So, g = 4.8 cm