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timofeeve [1]
2 years ago
11

The product of -5/7 and -2/5 is​

Mathematics
2 answers:
melisa1 [442]2 years ago
6 0

Answer:

2/7

Step-by-step explanation:

Radda [10]2 years ago
4 0

Answer:

Asnwer:3/2 you divide and simplify you get 6/4 then you divide and there is your answer!! :)

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The formula to find the period of orbit of a satellite around a planet is (T^2) = (4pi^2/ gm) r3 where r is the orbit’s mean rad
Inga [223]
See the attached graphic to see this solved for "r".
You should be very careful about stating the units for each of those variables.
time in seconds
radius in meters
mass in kilograms
G = 6.674 x 10^-11 m^3 / (kilograms * seconds²)
Also, it would be worth your while to go to this web page http://www.1728.org/kepler3a.htm
It has a calculator and other information about Kepler's Third Law.


7 0
3 years ago
A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot
Olegator [25]

Answer:

The ratio of the drag coefficients \dfrac{F_m}{F_p} is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, c_{m} = The drag coefficient of the prototype, c_{p}

The medium of the test for the model, \rho_m = The medium of the test for the prototype, \rho_p

The drag force is given as follows;

F_D = C_D \times A \times  \dfrac{\rho \cdot V^2}{2}

We have;

L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m

Therefore;

\dfrac{L_p}{L_m}  = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2

\dfrac{L_p}{L_m}  =\dfrac{17}{1}

\therefore \dfrac{L_p}{L_m}  = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{c_p \times A_p \times  \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times  \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}

\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3

\dfrac{F_m}{F_p}  = \left( \left\dfrac{1}{17} \right)^3= (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients \dfrac{F_m}{F_p} ≈ 0.0002.

5 0
2 years ago
0.3 km = ? mi. rounded to the nearest hundred​
Sergio [31]

Answer:

0.19

Step-by-step explanation:

There are approximately .62 miles in a kilometer

6 0
3 years ago
Read 2 more answers
The table shows the time Merrida spent driving and the number of miles she drove. She drove the same number of miles each hour.
Oksi-84 [34.3K]

Answer:

35 miles per hour

Step-by-step explanation:

175 -140 = 35

35/1 = 35

6 0
3 years ago
According to the rational root theorem, what are all the potential rational roots of f(x)=5x^3-7x+11
Genrish500 [490]

Answer:

\pm11,\pm1,\pm\frac{11}{5},\pm\frac{1}{5}

Step-by-step explanation:

The given polynomial function is

f(x)=5x^3-7x+11

According to the Rational Roots Theorem, the ratio of all factors of the constant term expressed over the factors of the leading coefficient.

The potential rational roots are

\pm\frac{11}{1}=\pm11

\pm\frac{1}{1}=\pm1

\pm\frac{11}{5}

\pm\frac{1}{5}

4 0
3 years ago
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