The points you are looking for are the midpoints of segments JL and JK.
J(-2, -1), K(4, -5), L(0, -5)
The midpoint of segment JL is
(-2 + 0)/2, (-1 + (-5))/2) = (-2/2, -6/2) = (-1, -3)
The midpoint of segment JK is
(-2 + 4)/2, (-1 + (-5))/2) = (2/2, -6/2) = (1, -3)
Answer: The coordinates are (-1, -3), (1, -3)
Answer:
10
Step-by-step explanation:
Plug the numbers into the distance formula:
Then solve:
You get 10
Answer:
B- x > -6
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
Step-by-step explanation:
<u>Step 1: Define</u>
-4x + 12 < 36
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Subtraction Property of Equality] Subtract 12 on both sides: -4x < 24
- [Division Property of Equality] Divide -4 on both sides: x > -6
Answer: x² + y² - 2x - 8y + 13 = 0
Step-by-step explanation:
the equation of the circle is in the form (x - a)² + (y - b)² = r²
where (a,b) is the center of the circle and r is the radius
hence the equation is
(x - 1)² + (y - 4)² = 2²
x²-2x+1+y²-8y+16= 4
x²+ y² -2x- 8y + 17 =4
x² + y² - 2x - 8y = -13
x² + y² - 2x - 8y + 13 = 0
Answer:
the real solutions are the ones that actually cross the x-axis.
so the real solutions are (-5, 0) (-1,0) (4,0) and (8,0)
