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kupik [55]
3 years ago
13

(PLEASE HELP GIVING BRAINILEST)

Mathematics
1 answer:
SOVA2 [1]3 years ago
7 0

Answer:

1. 37.5 metres.

2. 33.33 metres (May be wrong due to the answer but I used the correct solution to find the answer)

3. Refer to explanation.

Step-by-step explanation:

1. Find out how much Logan and Mila both swam.

1/3 of an hour =

60 minutes ÷ 3 = 20 minutes

Logan swam 750 metres for 20 minutes.

Mila swam 2/3 of Logan's distance.

Find out how much is 1/3 of Logan's distance in 1/4 of an hour.

3/3 = 750

1/3 = 750 ÷ 3 = 250

2/3 = 250 x 2 = 500

1/4 of an hour =

60 minutes ÷ 4 = 15 minutes

Mila swam 500 metres in 15 minutes.

To find out Logan's average swimming speed, here's the formula:

Total distance/total elapsed time

So it is 750/20 which is 37.5 metres.

2. Use the same formula I mentioned above in question 1 for average swimming speed, so it is...

500/15 = 33.33 metres

3. Other ways to compare Mila's and Logan's swimming speed is to find out the difference of the distance of how long they swam.

Use Mila's average swimming speed and find out how much metres she would swim if she swam for 20 minutes.

33.33 metres x 20 minutes = 666.6 metres

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3 years ago
A bacteria culture starts with 100 bacteria and doubles in size every half hour.
taurus [48]

Answer:

y=25600

y=100(2)^{2t}

y=252

Step-by-step explanation:

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y=100(2)^{2 \cdot 4}\\y=25600

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y=100(2)^{2t}

convert 40 seconds into hour

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y=100(2)^{2\frac{2}{3} }\\y=100(2)^{\frac{4}{3} }\\\\y=252

The graph is attached below

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3 years ago
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3 0
2 years ago
The population for Gulch Dry has been declining according to the function P(t)= 8000. 2^-t/29 where t is the number of years sin
Iteru [2.4K]
A)

\bf 1990-1910=80\leftarrow t
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P(t)=8000(2)^{-\frac{t}{29}}\implies P(80)=8000(2)^{-\frac{80}{29}}
\\\\\\
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and surely you know how much  that is.

b)

\bf P(t)=125\\\\\\  125=8000(2)^{-\frac{t}{29}}\implies \cfrac{125}{8000}=2^{-\frac{t}{29}}\implies \cfrac{1}{64}=2^{-\frac{t}{29}}
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\textit{now we take log to both sides}
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log\left( \frac{1}{64} \right)=log\left( 2^{-\frac{t}{29}} \right)\implies log\left( \frac{1}{64} \right)=-\frac{t}{29}log\left( 2 \right)
\\\\\\
log\left( \cfrac{1}{64} \right)=-\cfrac{tlog(2)}{29}\implies \cfrac{-29log\left( \frac{1}{64} \right)}{log(2)}=t\implies 174=t

since in 1910 t = 0, 174 years later from 1910, is 2084, so in 2084 they'll be 125 exactly, so the next year, 2085, will then be the first year they'd fall under that.
6 0
3 years ago
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