The side length in the y-direction is 9-6 = 3 units. (sides ab and cd)
The side length in the x-direction is 7-2 = 5 units. (sides bc and ad)
The matchings are as follows:
1) 2=3 , 4 =5 (Given)
2) 1 =3 (vertical angles are equal)
3) 1 =2 (substitution)
4) VR=VR (Reflexive)
5) Triangle VSR congruent to Triangle VTR (ASA)
6) RS=RT CPCTE
The matchings are done above. The triangles are congruent as per ASA congruency as two angles and corresponding side is equal.
since 2 =3 and 1 = 3 we get 1=2
By CPCTE we have RS =RT
Answer:
final answer:
y-1= 3x_6
To solve our given problem, we must find the equation of the tangent line of the function f(x)=(x−1)3, at x=2.
.
.
Answer:
10 friends
Step-by-step explanation:
we know that
The formula of the sum is equal to
![sum=\frac{n}{2}[2a1+(n-1)d]](https://tex.z-dn.net/?f=sum%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a1%2B%28n-1%29d%5D)
where
a1 is the first term
n is the number of terms (number of friends)
d is the common difference in the arithmetic sequence
In this problem we have
----> the common difference
substitute in the formula and solve for n
![275=\frac{n}{2}[2(5)+(n-1)(5)]](https://tex.z-dn.net/?f=275%3D%5Cfrac%7Bn%7D%7B2%7D%5B2%285%29%2B%28n-1%29%285%29%5D)
![550=n[10+5n-5]\\ \\550=10n+5n^{2} -5n\\ \\5n^{2}+5n-550=0](https://tex.z-dn.net/?f=550%3Dn%5B10%2B5n-5%5D%5C%5C%20%5C%5C550%3D10n%2B5n%5E%7B2%7D%20-5n%5C%5C%20%5C%5C5n%5E%7B2%7D%2B5n-550%3D0)
Solve the quadratic equation by graphing
The solution is n=10
see the attached figure
therefore
She had 10 friends who got stickers
