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2 years ago

C. Solve 1/2 x - (x+3)<1/3(x-1)

Mathematics

1 answer:

MAVERICK [17]2 years ago

7 0

Answer: x = 28

Step-by-step explanation:

Let's solve your equation step by step!

3/8x + 15/2 = 18

Step 1: Subtract 15/2 from both sides.

3/8x + 15/2 - 15/2 = 18 - 15/2

3/8x = 21/2

Step 2: Multiply both sides by 8/3

(8/3) * (3/8x) = (8/3) * (21/2)

Step 3. Calculate

x = 28

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What is the value of x for part A and part B

GuDViN [60]

Part A :

So the two sides are equivalent,

$9x - 18 = 3x$

Solve for x and get 3.

~~

Answer : x = 3

~~

Part B :

To find JM, simply substitute x for 3 and solve,

$9(3) - 18$
$27 - 18 = 9$
~^

Answer : JM = 9

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey

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3 years ago

kherson [118]

The answer is j.
y = |x - 1|

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3 years ago

Select the correct answer. Find the sum of 2 + (-) + 3

White raven [17]

Answer:

-1

Step-by-step explanation:

Firstly + and (-) become - and again same thing will happen

Hope it helps you....☺

8 0

3 years ago

The winner of a 100 mile race drove his car to victory at a rate of 120.1229 mph. What was his time to the nearest thousandth of

Zigmanuir [339]

Answer:

$t=1.201\ \text{hour}$

Step-by-step explanation:

Given that,

Distance, d = 100 mile

Velocity of the winner, v = 120.1229 mph

We know that velocity of an object is equal to distance per unit time. Let t is the time. So,

$v=\dfrac{d}{t}\\\\t=\dfrac{d}{v}\\\\t=\dfrac{120.1229}{100 }\\\\t=1.201229\ \text{hour}\\\\\text{Round to the nearest thousandth}\\\\t=1.201\ \text{hour}$

Hence, 1.201 hour is taken by the winner.

8 0

2 years ago

20 how much metal is needed to smelt a cubical metal box with outer side 12 inches long if the thickness of its walls should be

guajiro [1.7K]

The volume of the metal box if the box was completely solid (V1), is:

V1=(12 inches)³
V1=1728 inches³

As there are 3 inches of metal on both sides, the widht if the metal box was not completely solid, is:

W=12 inches-(3 inchesx2)
W=6 inches

Then, the volumen of the no solid metal box is:

V2=(6 inches)³
V2= 216 inches³

Therefore, the volume of metal needed to smelt the cubical metal box, is:

V3=V1-V2
V3=1728 inches³-216 inches³
V3=1512 inches³

6 0

3 years ago

C. Solve 1/2 x - (x+3)<1/3(x-1)​

C. Solve 1/2 x - (x+3)<1/3(x-1)