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goldenfox [79]
3 years ago
13

when using tables and verbal descriptions to describe a linear relationship why is it useful to convert from one to another

Mathematics
1 answer:
zheka24 [161]3 years ago
4 0

Linear relationships can be expressed either in a graphical format where the variable and the constant are connected via a straight line or in a mathematical format where the independent variable is multiplied by the slope coefficient, added by a constant, which determines the dependent variable.

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I just failed algebra for the third time someone help pls<br> Just tell me what to do
Nikolay [14]

Answer:

study lol

Step-by-step explanation:

6 0
3 years ago
José vende dos bicicletas, cada una a 198 soles. Si en una ganó el 10% y en la otra perdió el 10%. ¿Cuanto ganó o perdió pir la
Arte-miy333 [17]

Answer:

I win 10% = 217.8

I lost 10% = 178.2

217.8 + 178.2 = 396

198 + 198 = 396

396 = 396

I neither gain nor lose anything: V

Step-by-step explanation:

3 0
3 years ago
I need help with completing the reasons for the proof. The first 3 statments are given. ​
Oxana [17]

Answer:Two-column, paragraph, and flowchart proofs are three of the most common geometric proofs. They each offer different ways of organizing reasons and statements so that each proof can be easily explained.

Step-by-step explanation:

4 0
3 years ago
Solve the inequality: (x+3)(x−4)&lt;−12
melamori03 [73]

Answer:

0<x<1

Step-by-step explanation:

(x+3)(x−4)<−12

FOIL

x^2 -4x+3x -12 <-12

x^2 -x -12 <-12

Add 12 to each side

x^2 -x -12+12 <-12+12

x^2 -x <0

Factor out an x

x(x-1) <0

Using the zero product property

x(x-1) =0

x=0  x-1=0

x=0  x=1

Check the ranges

x<0

x(x-1) <0        

- * - >0

False

0<x<1

x(x-1) <0        

+ * - <0

True

x>1

x(x-1) <0        

+ * + >0

False

3 0
3 years ago
Simultaneous equations<br> x^2+3xy=10<br> x=2y
satela [25.4K]

9514 1404 393

Answer:

  (x, y) = (-2, -1) or (2, 1)

Step-by-step explanation:

Substitute for x in the first equation:

  (2y)^2 +3(2y)y = 10

  10y^2 = 10

  y^2 = 1

  y = ±1

  x = 2y = ±2

Solutions are (x, y) = (-2, -1) or (2, 1).

8 0
3 years ago
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