Can any one help me i really need it

Mathematics

2 answers:

goblinko [34]3 years ago

6 0

Answer:

i got 722.5, Not sure if this is right but it's what I got

Vilka [71]3 years ago

5 0

34 try the app Cymath it’s great for math

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A car traveled 88 km in 1 hour, 90 km in the next 2 hours, and then 76 km in 1 hour before reaching its destination. what was th

luda_lava [24]

The formula for Average speed = $\frac{Total Distance}{Total Time}$

The car travels 80 km in 1 hour.

Then the car travels 90 km in 2 hours.

And finally the car travels 76 km in 1 hour

So the total distance covered by the car = 80 + 90 + 76 = 246 km

The total time taken to cover this distance = 1 + 2 + 1 = 4 hours.

So average speed = $\frac{246}{4}= 61.5$

The average speed of the car is 61.5 km / h

3 0

3 years ago

(question is on picture linked)

nalin [4]

here y+13=15

so we got y=2

then y+13+x+12=30

then we will get x=3

7 0

2 years ago

The prior probabilities for events A1 and A2 are P(A1) = 0.35 and P(A2) = 0.50. It is also known that P(A1 ∩ A2) = 0. Suppose P(

forsale [732]

Answer:

Step-by-step explanation:

Hello!

Given the probabilities:

P(A₁)= 0.35

P(A₂)= 0.50

P(A₁∩A₂)= 0

P(BIA₁)= 0.20

P(BIA₂)= 0.05

Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)

Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.

Considering that $P(BIA)= \frac{P(AnB)}{P(A)}$ you can clear the intersection from the formula $P(AnB)= P(B/A)*P(A)$ and apply it for the given events: