This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :) Anyway...
h=-2t^2+9t+11
A)
dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached
dh/dt=0 only when 4t=9, t=2.25 seconds
h(2.25)=21.125 ft (21 1/8 ft)
B)
As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.
C)
The squirrel reaches the ground when h=0...
0=-2t^2+9t+11
-2t^2-2t+11t+11=0
-2t(t+1)+11(t+1)=0
(-2t+11)(t+1)=0, since t>0 for this problem...
-2t+11=0
-2t=-11
t=5.5 seconds.
Answer:
5(3√x) +9(3√x) = 15√x+27√x= 42√x
5∛x + 9∛x = 14∛x
Step-by-step explanation:
Z=118 as vertically opposite angles are the same
x= (8x-50)
Answer:
1 
Step-by-step explanation:
5/3 = 3/3 * 2/3
3/3 = 1
So the answer is 1
Answer:
28
Step-by-step explanation:
16−(−12)
=16−(−12)
=16+12
=28
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28 is your answer
(Hope it helps)
