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ollegr [7]
3 years ago
5

20 POINTS ANSWER FAST!

Mathematics
2 answers:
Gennadij [26K]3 years ago
5 0

Answer:

1. 83% 2.17%

Step-by-step explanation:

Dominik [7]3 years ago
5 0

Answer:

sorry no a need the point

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2 years ago
Can anyone help me I don’t understand plz
Citrus2011 [14]

There we have an information of two functions g(t)\,  and \, h(t)

Using this two functions g(t)\,  and \, h(t), we need to find the composition of functions (h\circ g)(t).

The composition of two functions h and g is the new function , by performing g first and then performing h.

(h\circ g)(t)=h(g(t))

g(t)=3(t+1)

h(t)=2t

Composition of h and g (t) = (h\circ g)(t)

=h(g(t))

First plugin the value of g(t)=3(t+1)

h(g(t))=h(3(t+1))

=h(3t+3)

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That is, to replace t by 3t+3,

=2(3t+3)

Now distribute 2 into 3t+3,

=6t+6

Now plug in t=-6,

h(g(-6))=6(-6)+6

=-36+6 \\ =-30

Thus the solution is (D). h(g(-6))=-30.

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3 years ago
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