You should try to restate the question more descriptively.
The y-intercept is (0,-11), which is option C.
Area of the 3 rectangles that make up the prism:
30 * 25 + 30 * 17 + 30 * 28 = 2100
Area of the two triangles at either end:
Use bh/2
(15 * 28)/2 = 210
There are two so it’s 420
2100 + 420 = 2520cm^2
Total height of lumber, H = 10 1/2 feet = 21/2 feet .
Height of side panel, h = 5 2/3 feet = 17/3 feet .
Now,
Extra lumber required, L = 2 × Height of side panel - Total height of lumber
![L=[2\times (\dfrac{17}{3})]-\dfrac{21}{2}\\\\L = \dfrac{5}{6}\ feet](https://tex.z-dn.net/?f=L%3D%5B2%5Ctimes%20%28%5Cdfrac%7B17%7D%7B3%7D%29%5D-%5Cdfrac%7B21%7D%7B2%7D%5C%5C%5C%5CL%20%3D%20%5Cdfrac%7B5%7D%7B6%7D%5C%20feet)
Therefore, extra lumber required is
feet.
Hence, this is the required solution.
By definition
... sec(θ) = 1/cos(θ) . . . . trig identity
... sec(θ) = 1/(9/10) . . . . substitute the given value, then simplify to ...
... sec(θ) = 10/9