What is 539 rounded to the nearest hundred?

Sandra needs to obtain a random sample of 20 students from her school, in order to do a project for her statistics class. Which

ser-zykov [4K]

Answer: D) At the next school assembly, choose one student from each of 20 randomly selected rows.

Step-by-step explanation:

A wouldnt be correct because it is all students from the spots program

B isnt correct because it is 10 girls and 10 boys from the girls' and boys' soccer teams

C wouldnt be correct because it would be the first 20 students she sees once she leaves statistics class

D is the only unbiased, completely random selection choice.

3 0

4 years ago

Read 2 more answers

How to solve this question I am stuck <br> please help

Pachacha [2.7K]

Answer:

x=3

Step-by-step explanation:

WY is an angle bisector, which makes both sides equivalent (it’s an isosceles triangle)

4 0

3 years ago

Who's good at Fractions? Will give Brainlest to who answers.

Inga [223]

You need to add two mixed numerals.
One is positive and one is negative.
To add a positive number and a negative number, first take the absolute value of both, making them both positive. Then subtract the smaller absolute value from the larger absolute value. Finally, the sign of the answer is the same sign as the number that has the larger absolute value.

The numbers are -4 5/8 and 2 1/8

Take absolute values:
|-4 5/8| = 4 5/8
|2 1/8| = 2 1/8

Subtract the smaller absolute value from the larger absolute value.

4 5/8 - 2 1/8 = 2 4/8 = 2 1/2

The greater absolute value is 4 5/8.
Since the number with the larger absolute value was -4 5/8, a negative number, the answer is negative, -2 1/2

-4 5/8 + 2 1/8 = - 2 1/2

6 0

3 years ago

What is the y-value of the vertex of the function f(x)=-(x-3)(x+11)

lutik1710 [3]

so, this is a quadratic equation, meaning two solutions, and we have a factored form of it, meaning you can get the solutions by simply zeroing out the f(x).

$\bf \stackrel{f(x)}{0}=-(x-3)(x+11)\implies 0=(x-3)(x+11)\implies x= \begin{cases} 3\\ -11 \end{cases} \\\\\\ \boxed{-11}\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}-4\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}\boxed{3}$

so the zeros/solutions are at x = 3 and x = -11, now, bearing in mind the vertex will be half-way between those two, checking the number line, that midpoint will be at x = -4, so the vertex is right there, well, what's f(x) when x = -4?

$\bf f(-4)=-(-4-3)(-4+11)\implies f(-4)=7(7)\implies f(-4)=49 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{vertex}{(-4~~,~~49)}~\hfill$

7 0

3 years ago

Given the functions f(x) = 3x2, g(x) = x2 − 4x + 5, and h(x) = –2x2 + 4x + 1, rank them from least to greatest based on their ax

worty [1.4K]

F(x) = 3x²
$x = \frac{-b}{2a} = \frac{-0}{2(3)} = \frac{0}{6} = 0$
f(x) = 3x²
f(0) = 3(0)²
f(0) = 3(0)
f(0) = 0
(x, f(x)) = (0, 0)

g(x) = x² - 4x + 5
$x = \frac{-b}{2a} = \frac{-(-4)}{2(1)} = \frac{4}{2} = 2$
g(x) = x² - 4x + 5
g(2) = (2)² - 4(2) + 5
g(2) = 4 - 8 + 5
g(2) = -4 + 5
g(2) = 1
(x, g(x)) = (2, 1)

h(x) = -2x² + 4x + 1
$x = \frac{-b}{2a} = \frac{-4}{2(-2)} = \frac{-4}{-4} = 1$
h(x) = -2x² + 4x + 1
h(1) = -2(1)² + 4(1) + 1
h(1) = -2(1) + 4 + 1
h(1) = -2 + 5
h(1) = 3
(x, h(x)) = (1, 3)

6 0

3 years ago