70 palm trees are on that street
Let us solve this system of equations by using the elimination method. Adding the 2 equations, we get
9x + 5y - 9x + 4y = -33 + 6
9y = -27
y = -3
Substituting this value of y in the first equation, we get
-9x + 4(-3) = 6
-9x - 12 = 6
9x + 12 = -6
9x = -18
x = -2
Therefore, x = -2, and y = -3. Hope this helps! If you have any questions, feel free to ask.
$2.37 (the amount he spent on groceries) + <span>35¢ (or $0.35 he could spend on candy) = $2.72
Now you subtract this number from the five dollar bill to get the change.
5 - 2.72 = $2.28
His change was $2.28.
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Answer:
Step-by-step explanation:
Given points are 
And given transformation is 
We will start from left to right.
First transformation is reflection about x-axis.
When we reflect about x-axis 
So, ![(-1,-8)=[-1,-(-8)]=(-1,8)](https://tex.z-dn.net/?f=%28-1%2C-8%29%3D%5B-1%2C-%28-8%29%5D%3D%28-1%2C8%29)
Now next transformation is dilation with a factor 4.
If we do dilation with a factor 
to the point 
New co-ordinates after dilation became 
So, 
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.
2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.
3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.
4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.
Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
