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Veronika [31]
3 years ago
13

-3=3w + 6 solve for w

Mathematics
2 answers:
likoan [24]3 years ago
7 0
W= -3

( replace w with -3 )

3* -3 = -9
-9 + 6 = -3
Nina [5.8K]3 years ago
6 0

Answer:

w=3

Step-by-step explanation:

3w=+6+3

3w=9

w=9÷3

w=3

how I get?

3×w

if 3 move to the front it's goes to ÷

so 9÷3

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Answer:

4, 4, and 8

Step-by-step explanation:

2 cups * 2 marshmallows per cup = 4 marshmallows

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mamaluj [8]

Using the given equation:

10PI/X = 240/360

Cross multiply:

(10PI*360) = (240*X)

3600PI = 240X

Divide both sides by 240:

X = 3600PI / 240

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3 0
3 years ago
Goals scored by a hockey team in successive matches are 5,7,4,2,4,0,5,5 and 3. What is the number of goals, the team must score
Stels [109]

Answer:

5

Step-by-step explanation:

Total goals /total no. of matches = 4

5+7+4+2+4+0+5+5+3+x / 10 = 4

35 + x = 4 × 10

x = 40 - 35

x = 5

So, the team must score 5 inorder to get the average of 4 goals per match.

6 0
2 years ago
What is the solution to this system of equations?
Ede4ka [16]

Answer:

First choice.

Step-by-step explanation:

You could plug in the choices to see which would make all the 3 equations true.

Let's start with (x=2,y=-6,z=1):

2x+y-z=-3

2(2)+-6-1=-3

4-6-1=-3

-2-1=-3

-3=-3 is true so the first choice satisfies the first equation.

5x-2y+2z=24

5(2)-2(-6)+2(1)=24

10+12+2=24

24=24 is true so the first choice satisfies the second equation.

3x-z=5

3(2)-1=5

6-1=5

5=5 is true so the first choice satisfies the third equation.

We don't have to go any further since we found the solution.

---------Another way.

Multiply the first equation by 2 and add equation 1 and equation 2  together.

2(2x+y-z=-3)

4x+2y-2z=-6 is the first equation multiplied by 2.

5x-2y+2z=24

----------------------Add the equations together:

9x+0+0=18

9x=18

Divide both sides by 9:

x=18/9

x=2

Using the third equation along with x=2 we can find z.

3x-z=5 with x=2:

3(2)-z=5

6-z=5

Add z on both sides:

6=5+z

Subtract 5 on both sides:

1=z

Now using the first equation along with 2x+y-z=-3 with x=2 and z=1:

2(2)+y-1=-3

4+y-1=-3

3+y=-3

Subtract 3 on both sides:

y=-6

So the solution is (x=2,y=-6,z=1).

8 0
3 years ago
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