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kotykmax [81]
3 years ago
10

A hairstylist charges $15

Mathematics
1 answer:
katovenus [111]3 years ago
4 0

Answer:

Ok.....

Step-by-step explanation:

Was that a question or was that the price you paid for getting a hair cut.

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\implies \tan x = \dfrac 12 ~~ \text{or} ~~  \tan x =-1~~~ ;[\text{Substitute back u =tan x}]\\\\\text{Now,}~ \\\\\tan x = -1,\\\\\implies x = n\pi - \dfrac{\pi}4\\\\\\\text{For interval,}~ [0,2\pi) \\\\x = \dfrac{3\pi}4, \dfrac{7\pi}4\\\\\text{In degrees,}~ x = 135^{\circ}, x =315^{\circ}\\\\\tan x = \dfrac 12\\\\\implies x = n\pi + \tan^{-1} \left(\dfrac 12 \right)\\\\\text{For interval} ~[0,2\pi),\\\\

x=\tan^{-1} \left(\dfrac 12 \right),  \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\text{in degrees,}   ~~x=\tan^{-1} \left(\dfrac 12 \right),  \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\\\\text{Combine all solutions:}\\\\x=\dfrac{3\pi}4, \dfrac{7\pi}4, \tan^{-1} \left(\dfrac 12 \right),  \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\

\text{In degrees,}~ x = 135^{\circ},~315^{\circ},~\tan^{-1} \left(\dfrac 12 \right),  \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]

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