Answer:
associative property
Step-by-step explanation:
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer:
<u>BC = 3.1666</u>
Step-by-step explanation:
To solve this you need to know that cosine∅ = adjacent/hypotenuse. We already know that hypotenuse = 5 and that ∅ = 70*. By substituting these in you will get cosine 70* = adjacent/5. Evaluate cosine 70* on the calculator and get 0.633... Multiply both sides by 5 and get adjacent is about equal to 3.1666. Because BC is the adjacent side of the triangle, this is the length of BC.
<span>Write the equation of the line that satisfies the given conditions, Express the final equation in standard form. Contains the point (2,5) and is parallel to the line x-2y=-5
The given equation can be written 2y=x+5; y = (1/2)x+(5/2)
It's slope is 1/2
So any line parallel to it has slope = 1/2
If the line also passes thru (2,5), 5 = (1/2)2+b; b=4
Therefore the equation you want is y = (1/2)x+4</span>