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IceJOKER [234]
2 years ago
10

Hi can someone please help me with my math work?

Mathematics
1 answer:
Eva8 [605]2 years ago
4 0

Answer:

Integers are 7, 8, 9

Step-by-step explanation:

Let three positive consecutive integers are (n - 1), n, (n + 1)

If the product of the second and the third integer is 72,

n(n + 1) = 72

n² + n = 72

n² + n - 72 = 0

n² + 9n - 8n - 72 = 0

n(n + 9) - 8(n + 9) = 0

(n - 8)(n + 9) = 0

(n - 8) = 0 ⇒ n = 8

(n + 9) = 0 ⇒ n = -9

For n = 8,

Integers will be ⇒ 7, 8, 9

For n = -9,

Integers will be ⇒ -10, -9, -8

Since, all integers are positive,

7, 8, 9 will be the answer.

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Maru [420]
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<span>Then it's just plug & grind: </span>

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3 years ago
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Answer:

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we use Pythagoras theorem that is:

c^{2} =a^{2} +b^{2}

c = \sqrt{a^{2} +b^{2} }

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c = ?

a = 40

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putting them in formula,

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For question 2:

c = ?

a = 12

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putting them in formula,

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For question 3:

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putting them in formula,

c^{2} =a^{2} +b^{2}

35^{2} = 20^{2} + b^{2}

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c = 37

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putting them in formula,

c^{2} =a^{2} +b^{2}

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4 0
2 years ago
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Kisachek [45]

Answer:

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Step-by-step explanation:

Hi Lasagna!

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