Ask question

Ask question

All categories

3 years ago

5

Assume Cylinder A and Cone B are the same height and the bases have the same radius. If A has a volume of 18π cm3, what is the v

olume of B?

2 answers:

Rashid [163]3 years ago

7 0

Answer:

The volume of cone is $6\pi\ cm^{3}.$

Step-by-step explanation:

Formula

$Volume\ of\ a\ cylinder = \pi r^{2}h$

$Volume\ of\ a\ cone = \pi\ r^{2}\frac{h}{3}$

Where r is the radius and h is the height .

As given

Assume Cylinder A and Cone B are the same height and the bases have the same radius. If A has a volume of 18π cm³.

Thus

$Volume\ of\ cone = \frac{1}{3}\times Volume of cylinder$

$Volume\ of\ cone = \frac{18\pi }{3}$

$Volume\ of\ cone = 6\pi\ cm^{3}$

Therefore the volume of cone is $6\pi\ cm^{3}.$

Artemon [7]3 years ago

5 0

The volume of a cone is (1/3) that of its similar cylinder.
Thus the volume of the cone B would be: $6 \pi cm^{3}$

You might be interested in

Which inequality represents the values of x that ensure triangle ABC exists? a triangle with side lengths of 6.5 units, 3.5 unit

nikdorinn [45]

Answer:

1 < x < 7.5

Step-by-step explanation:

This problem can be solved using given below property of triangle.

Sum of two sides is always greater than third side of triangle.

Difference of two sides is always lesser than third side of triangle.

_______________________________________________

Given

sides length

6.5 units

3.5 units

Third side is 2.5 + x

using the property, Sum of two sides is always greater than third side of triangle.

6.5 + 3.5 > 2.5 +x

=>10 >2.5 + x

=>2.5 + x< 10

=> x< 10 -2.5

=> x < 7.5

using the property, Difference of two sides is always lesser than third side of triangle.

6.5 - 3.5 > 2.5 +x

=>3.5 > 2.5 +x

=> 2.5 +x > 3.5

=> x > 3.5 - 2.5

=> x > 1

combining both we have

1 < x < 7.5

out of the given option none is 1 < x < 7.5

hence, correct answer will be 1 < x < 7.5 and wrong option can be claimed by student.

8 0

2 years ago

Read 2 more answers

The product of a number and 9, increased by 4, is 58. Find the number

ella [17]

Answer:

first do 58-4 which is 54 then do 54/ 9 which is 6 so the number is 6

8 0

2 years ago

Read 2 more answers

Zipora wants to construct a triangle that has the following angle measures: 50°, 75°, and 55°. How many triangles can she make?

Alborosie

As sum of all angles of triangle equal to 180 degrees.
First we have to add the angles.
50+75+55
=50+130
=180 degrees

Answer: Zipora can construct exactly one triangle.

4 0

3 years ago

Read 2 more answers

Which of the following is a factor if 4x^2 - 4x - 3?

Svetradugi [14.3K]

Answer:

c

Step-by-step explanation:

6 0

1 year ago

. Given ????(5, −4) and T(−8,12):

damaskus [11]

Answer:

a) $y=\dfrac{13x}{16}-\dfrac{129}{16}$

b) $y = \dfrac{13x}{16}+ \dfrac{37}{2}$

Step-by-step explanation:

Given two points: $S(5,-4)$ and $T(-8,12)$

Since in both questions,a and b, we're asked to find lines that are perpendicular to ST. So, we'll do that first!

Perpendicular to ST:

the equation of any line is given by: $y = mx + c$ where, m is the slope(also known as gradient), and c is the y-intercept.

to find the perpendicular of ST <u>we first need to find the gradient of ST, using the gradient formula.</u>

$m = \dfrac{y_2 - y_1}{x_2 - x_1}$

the coordinates of S and T can be used here. (it doesn't matter if you choose them in any order: S can be either x_1 and y_1 or x_2 and y_2)

$m = \dfrac{12 - (-4)}{(-8) - 5}$

$m = \dfrac{-16}{13}$

to find the perpendicular of this gradient: we'll use:

$m_1m_2=-1$

both $m_1$ and $m_2$ denote slopes that are perpendicular to each other. So if $m_1 = \dfrac{12 - (-4)}{(-8) - 5}$ , then we can solve for $m_2$ for the slop of ther perpendicular!

$\left(\dfrac{-16}{13}\right)m_2=-1$

$m_2=\dfrac{13}{16}$ :: this is the slope of the perpendicular

a) Line through S and Perpendicular to ST

to find any equation of the line all we need is the slope $m$ and the points $(x,y)$ . And plug into the equation: $(y - y_1) = m(x-x_1)$

side note: you can also use the $y = mx + c$ to find the equation of the line. both of these equations are the same. but I prefer (and also recommend) to use the former equation since the value of 'c' comes out on its own.

$(y - y_1) = m(x-x_1)$

we have the slope of the perpendicular to ST i.e $m=\dfrac{13}{16}$

and the line should pass throught S as well, i.e $(5,-4)$ . Plugging all these values in the equation we'll get.

$(y - (-4)) = \dfrac{13}{16}(x-5)$

$y +4 = \dfrac{13x}{16}-\dfrac{65}{16}$

$y = \dfrac{13x}{16}-\dfrac{65}{16}-4$

$y=\dfrac{13x}{16}-\dfrac{129}{16}$

this is the equation of the line that is perpendicular to ST and passes through S

a) Line through T and Perpendicular to ST

we'll do the same thing for $T(-8,12)$

$(y - y_1) = m(x-x_1)$

$(y -12) = \dfrac{13}{16}(x+8)$

$y = \dfrac{13x}{16}+ \dfrac{104}{16}+12$

$y = \dfrac{13x}{16}+ \dfrac{37}{2}$

this is the equation of the line that is perpendicular to ST and passes through T

7 0

3 years ago