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Nookie1986 [14]
3 years ago
7

PLEASE HELP WITH THIS QUESTION ASAP!!!!!!!!!!!!!!

Mathematics
2 answers:
iren [92.7K]3 years ago
7 0
Wait what’s the question?
Reptile [31]3 years ago
4 0
I think the answer is 7.8 but I’m not for sure
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Whoever gets it right can have brainliest, but answer ASAP!
notka56 [123]

Answer:

512

Step-by-step explanation:

512

8 0
3 years ago
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he length of time to perform an oil change at a certain automobile repair shop is ap-proximately normally distributed with mean
Simora [160]

Answer:

56.75% probability that a mechanic can complete 16 oil changes in an eight-hour day

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29.5, \sigma = 3

What is the probability that a mechanic can complete 16 oil changes in an eight-hour day

16 oil changes in 8 hours is 2 changes per hour, that is, one each 30 minutes.

This probability is the pvalue of Z when X = 30. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 29.5}{3}

Z = 0.17

Z = 0.17 has a pvalue of 0.5675

56.75% probability that a mechanic can complete 16 oil changes in an eight-hour day

4 0
3 years ago
Composite Figures Question 5.<br> A. 28 m<br> B. 44 m<br> C. 22 m<br> D. 192 m
seropon [69]

Answer:

the answer is 22

Step-by-step explanation:

the answer is 22

7 0
3 years ago
1.) The commuter trains on the Red Line for the Regional Transit Authority (RTA) in Cleveland, OH, have a waiting time during pe
alisha [4.7K]

Answer:

a) For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:

X \sim Unif(a=0,b=8)

Where a and b represent the limits of the distribution.

b) f(x) = \frac{1}{8}= 0.125, a\leq x \leq b

And the height for this case would be 0.125

Step-by-step explanation:

Part a

For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:

X \sim Unif(a=0,b=8)

Where a and b represent the limits of the distribution.

Part b

For this case the density function would be given by:

f(x) = \frac{1}{8}= 0.125, a\leq x \leq b

And the height for this case would be 0.125

And f(x)= 0  for other case.

The cumulative distribution function would be given by:

F(x) = 0, x

F(x) = \frac{x-a}{b-a}= \frac{x}{8}, 0\leq x < 8

F(x) = 1, x\geq 8

3 0
3 years ago
Please help on number 23!!!
Rainbow [258]
Show us the polygon___
6 0
3 years ago
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