Answer:
the answer is 2
Step-by-step explanation:
So do
25x16=400
this shows how many raffle tickets were sold all together
Then do 400x$15 =$6000
So all together they raised $6000
The answer is 8. you are basically adding 13 to -5. so it would be 13-5=8.
The pile contains 17 quarters and 15 half-dollars.
Let <em>x</em> = the number of quarters and <em>y</em> = the number of half-dollars.
We have two equations:
(1) $0.25<em>x</em> + $0.50<em>y</em> = $11.75
(2) <em>x</em> = <em>y</em> +2
Substitute the value of <em>x</em> from Equation (2) into Equation (1).
0.25(<em>y</em>+2) + 0.50<em>y</em> = 11.75
0.25<em>y</em> + 0.50 + 0.50<em>y</em> = 11.75
0.75<em>y</em> = 11.75 – 0.50 = 11.25
<em>y</em> = 11.25/0.75 = 15
Substitute the value of <em>y</em> in Equation (2).
<em>x</em> = 15 + 2 = 17
The pile contains 17 quarters and 15 half-dollars.
<em>Check</em>: 17×$0.25 + 15×$0.50 = $4.25 + $7.50 = $11.75.
Answer:
10 SENIORS
Step-by-step explanation:
x=# of seniors
y=# of juniors
x+y=23, x=2y-7
- plug the value of x in the second equation into the first
- (2y-7)+y=23
- Remove parentheses
- 2y-7+y=23
- Combine like terms
- 3y-7=23
- Add 7 to BOTH sides
- 3y=30
- divide BOTH sides by 3
- 3y/3=30/3
- y=10
- There are 10 juniors in the class
- FINAL STEPS
- Plug y (which is 10) into the first equation
- x+y=23
- x+10=23
- subtract 10 from BOTH sides
- x=13
- Since X equals the number of seniors, there are 10 seniors in the class
