2/21, 16/28
Multiply by 2,3,4
Answer:
It is A, 65
Hope this helps!
Answer:
70 seconds
Step-by-step explanation:
Given that;
The initial velocity
of the bullet fired = 1120 ft/s
Initial height h = 8 feet
The expression to determine how many seconds it takes the bullet to hit the ground is:

Thus;
Replacing the value of
= 1120 and h = 0 (i.e. when h =0) in the above expression; we have:


= -16t² + 1120t + 8
mulitiply through by (-)
= 16t² -1120t - 8
Divide through by 8
= 2t² - 140t - 1
The above expression forms a quadratic equation.
where;
a = 2
b = -140
c = - 1
So, by using the quadratic formula
, we have:






= 70
Thus, the time (in seconds) it took the bullet to it the ground = 70 seconds
Answer:
y = 7x - 5
Step-by-step explanation:
y=mx+b Where m is the slope and b is the y-intercept
y = 7 + 3x
y = 3x + 7
y = mx + b, therefore the y-intercept is 7.
3y = 6x + 12
y = 2x + 4
y = mx + b, therefore the y-intercept is 4.